Good luck,
Greater wavelength=TV. frequency= the number of wave cycles(peak, trough, peak) per time unit. The higher the frequency, the more times the wave cycles, and the shorter the wavelength.
Greater Energy=Ultraviolet lamp. By Placks constant, E(energy) =h(planck's constant which is the energy of a photon divided by it's frequency) / f(the frequency of that photon). Planck's constant is almost irrelevant, so the greater the frequency, the greater the energy.
Greater frequency=Ultraviolet lamp. Planck's constant and light spectrum.
Greater Momentum= Ultraviolet lamp. Electron diffraction, Wavelength=h(planck's constant) / momentum. rearrange it as M=h/W. The greater the wavelength, the smaller the momentum, and visa versa.
use de Broglie's wavelength: lambda = h/mv
A characteristic wavelength of an electron can be known as the DeBroglie Wavelength. It is a formula in physics which relays energy and momentum.
Because such a wavelength is way too small to be significant. The de Broglie wavelength is inversely proportional to an object's momentum (mass x speed).
Momentum, energy, frequency, and wave number (but not wave vector.)
Particles in motion will generally have kinetic energy, or momentum. Cumulative effects of motions of groups of particles (Brownian motion) is perceived as heat. According to the duality of matter (wave-particle), a moving particle can also be said to have a wavelength (De Broglie wavelength) associated with its mass and momentum.
The momentum of an X-ray beam does not change based on a wavelength of 5.0E-9m. The momentum of an x-ray beam is the same as the speed or momentum of light.
the electron would have the longer wavelength b/c the proton has more momentum and λ=h/p (λ is wavelength, h is planc's constant and p is momentum)
use de Broglie's wavelength: lambda = h/mv
A characteristic wavelength of an electron can be known as the DeBroglie Wavelength. It is a formula in physics which relays energy and momentum.
Wavelength equals Planck's Constant divided by momentum.
Physically, linear momentum is "stored force" as that momentum is dissipated. Consider the linear momentum of a train carrying coal coming to a stop, quickly.
This question is from Bohr's atomic model. The total length of the orbit is an integral multiple of the wavelength of an electron. The relation given by 2(pi)(radius)=n(wavelength), where n is the principal quantum number. Proof of this came later from De-Broglie's hypothesis, (wavelength)=h/(linear momentum) It is- (wavelength)=h/mv .....I From Bohr's model (Quantization of angular momentum), mvr=nh/2(pi) So, 2(pi)r=n(h/mv) From I, 2(pi)r=n(wavelength)
Because such a wavelength is way too small to be significant. The de Broglie wavelength is inversely proportional to an object's momentum (mass x speed).
Momentum, energy, frequency, and wave number (but not wave vector.)
yes. a body can have energy without momentum also. consider a body at a height 'h' m above the ground level , potential energy contained is = mgh but , as the velocity is 0 we can consider that the momentum of the body is 0
Particles in motion will generally have kinetic energy, or momentum. Cumulative effects of motions of groups of particles (Brownian motion) is perceived as heat. According to the duality of matter (wave-particle), a moving particle can also be said to have a wavelength (De Broglie wavelength) associated with its mass and momentum.
You can't think of momentum as simply "increasing" and "decreasing" - you have to consider momentum as a vector.If in a collision one object's momentum changes by a certain amount, call it "a", the momentum of the other object will change by the opposite amount, "-a" - both "a" and "-a" are vectors that add up to zero. If you consider only the magnitudes of the momentum, by conservation of energy the momenta can't both increase - but they can certainly both decrease, when objects collide head-on.