I think the questioner means to say that the (3214) is written in base-5, and he wants the same quantity in base-10.
(3214)5 = 3 x (53) + 2 x (52) + 1 x (51) + 4 x (50)
= 3 x (125) + 2 x (25) + 1 x (5) + 4 x (1)
= (375) + (50) + (5) + (4) = 434
It is 2000 + 30 + 2 and in base ten, that is 2032.
Commonly numbers are base 10 already.
2212
I would convert to base 10 , multiply and then convert back to base 6. 35 base 6 is 3 * 6 + 5 = 23 in base ten. 4 * 23 = 92 which is 2*36 + 3* 6 + 2 , in base 6 , the answer is 232 .
Okay - 43 in base five to base ten... The number 3 is easy - that stays the same. The number 4 is '5x4' which is 20. Add that to the 3 and you get 23. In base five - starting from the digit farthest right, every digit to the left, is five times the previous one.
That looks as if it already IS in base ten. If it isn't, you should know (and specify, if you ask) the base, before you can convert it.
26
It is 2000 + 30 + 2 and in base ten, that is 2032.
Commonly numbers are base 10 already.
2212
Convert the base 10 numeral to a numeral in the base indicated. 503 to base 5
Without knowing what base the number is written in it cannot be converted. Generally numbers in use are written in base 10
I would convert to base 10 , multiply and then convert back to base 6. 35 base 6 is 3 * 6 + 5 = 23 in base ten. 4 * 23 = 92 which is 2*36 + 3* 6 + 2 , in base 6 , the answer is 232 .
You can convert this to base ten by re-writing 3096 as a summation of hex powers: 3*16^3 + 0*16^2 + 9*16^1 + 5*16^0 = 12437 in base 10
1225 = 1 x 52 + 2 x 5 + 2 = 3710
Okay - 43 in base five to base ten... The number 3 is easy - that stays the same. The number 4 is '5x4' which is 20. Add that to the 3 and you get 23. In base five - starting from the digit farthest right, every digit to the left, is five times the previous one.
If a base of ten is to divide by ten that would be a decimal