string = Copyright © 2001 - 2011
ascii code of string is:
67 111 112 121 114 105 103 104 116 NULL NULL NULL 50 48 48 49 NULL 45 NULL 50 48 49 49
unicode is:
0043 006F 0070 0079 0072 0069 0067 0068 0074 0020 00A9 0020 0032 0030 0030 0031 0020 002D 0020 0032 0030 0031 0031
So, both are different
Convert string have a nice day to equivalent ascii code include spaces between words in the resultant ascii?
//C program to accept a string from user and //display its ascii value and //then display sum of all ascii value of strings #include<stdio.h> #include <string.h> int main() { char String[100]; int Sum,Index; Sum=0; //Sum is initially zero printf("Enter the string:\n"); gets(String); //Accept String from User for(Index=0;Index<strlen(String);Index++) { Sum+=(String[Index]); //Adds (the ASCII values of) the String characters. } printf("The sum is %d\n",Sum); //Printing it as %d gives the equivalent ASCII value. return 0; }
there is no such method using string copy
If you are referring to the ASCII code: The ASCII Code for a dot (.) is 46. The hexadecimal equivalent of this is 2E. You can find this, and all ASCII characters here: http://www.asciitable.com/.
atoi
Char 'a' is 97 decimal (61 hex) while char 'A' is 65 decimal (41 hex), a difference of 32 decimal (20 hex). Therefore test each char value in the char array (or string) using a for loop. If the char value is in the range 'a' to 'z', then subtract 32 decimal (20 hex). The following example demonstrates the method: void toupper(char* str, int len) { for(int i=0; i<len; ++i) { if(str[i]>='a' && str[i]<='z') str[i]-=32; } } To convert from upper to lower case, use the following instead: void tolower(char* str, int len) { for(int i=0; i<len; ++i) { if(str[i]>='A' && str[i]<='Z') str[i]+=32; } }
A null pointer is a pointer which does not point to any valid memory location, and usually contains the binary value "0" to represent this (this is language dependent). The ASCII null character is a character-sized zero value (in ASCII, it is an unsigned byte with a value of 0), and typically represents the end of a string (esp. as in C and C++). A null string is one that is zero characters of usable string data; in a length-based string, this means the length parameter is set to 0, and in an ASCII null-terminated string, means the first character is set to 0.
ascii
Overloads cannot differ by return type alone. The only way to achieve this is to use output arguments. Since the implementation is exactly the same regardless of the output type, you can use a function template to generate the overloads. #include<iostream> #include<sstream> template<typename T> bool convert(std::string& s, T& value) { std::stringstream ss; ss << s; if (ss >> value) return true; return false; } int main() { int i; float f; std::string s {"3.14"}; if (convert (s, i)) std::cout << '"' << s << "" = " << i << std::endl; if (convert (s, f)) std::cout << '"' << s << "" = " << f << std::endl; } Output: "3.14" = 3 "3.14" = 3.14
In order to find whether a character in a string is in uppercase or not, you need to use the ascii\unicode values of the character. You may want to use the following code-- String str="Your Sample String Here"; //(say you have this string) int l=str.length(); for(int i=0;i<l;i++) { char ch=str.charAt(i); if(ch>=65&&ch<=90) //Since the values of block letters in ASCII are from 65 to 90 System.out.println(ch); } //This program basically prints out the block letters, but you can modify it as you like, by changing the statement after 'if' as you want
Glass Giant is an online source which one can use to convert a picture to ASCII text art. The program is free and can be used directly on the website.
A string of characters followed by 0-9