The answer is most certainly "NO".
Due to the perpetual stupidity of British military small-arms people, they decided to adopt a different way of describing calibres than everyone else.
The "303 British" calibre is in fact a BIGGER calibre than the "308 Winchester" which is the proper family name of the 7.62NATO cartridge used in the British "SLR" which was a variant of the Belgian FN Fusil Automatique Legere.
Small dimensions make a huge difference in guns.
303 British bullets are of a nominal diameter 0.3125 inches.
7.62nato (and 308 Winchester) bullets should be 0.308"
The difference would cause greatly increased PRESSURE if a 303 bullet was fired in a SLR rifle.
Moreover, most "303 British" bullets weighed around 174 grains, whereas the SLR's 7.62 bullet was 144 grains. This extra weight would also increase pressures.
As the SLR was not a particularly strong action, damage to the gun and injury to the person shooting it could easily result from any attempt to shoot 303 bullets from a 7.62 rifle.Answer303 bullet means- the bullet fits the barrel of a rifle, diameter of that barrel being .303 inch. this has no relation with SLR rifle
as someone that has used enfield number 4 mk2, an L1A1 SLR and an L42A1 quite a lot I'd like to add my 2 penneth worth here..
the .303 is also a rimmed cartridge wheres the 7.62 is not, so if you did managed to get it to feed the bolt won't be able to fully close because of the thickness of the rim catching on the edge of the chamber, I guess the most likely result would be either the weapon wont fire or if the weapon does fire you would have a breach explosion possibly to the anoyance to anyone on your right,
incidently as a side note, a number of old .303 rifles were converted over to 7.62mm and used by the British army for a number of years, designated as L42A1's before being replaced by the L96, maybe this could be the cause for confusion
No. The L1A1 Self Loading rifle in in caliber 7.62 x51 mm (7.62 NATO) fires a rimless cartridge with a .308 bullet. The .303 Enfield cartridge is a different shape, has a rim, and fires a .311 bullet. If you compare the two cartridges, totally different in shape.
Both are equal in magnitude but in opposite direction
Bullet security cameras are not shaped like rifle bullets but are based upon the design of the bullets with similar aerodynamic design being used by both products.
They both fire the 50 BMG
The force exerted on the bullet and the recoil force against the rifleman, are equal to each other (for every action there is an equal and opposite reaction). The bullet has a very small mass, and the rifle/rifleman possess a large mass, force is equal to one half mass times velocity squared, F=m/2*v^2. So velocity of the bullet is the square root of twice force divided by mass, small mass equals large velocity. Another way of looking at this problem is to invoke the law of the conservation of momentum: mass(bullet)*muzzle_velocity(bullet) = mass(rifle)*recoil_velocity(rifle). This is an approximation that neglects the momentum carried away the propellant (both spent and unburned) that exits the muzzle after the bullet.
Provided the ground way out in front of the rifle is at the same elevation as the ground under the gun's barrel, both bullets hit the ground at the same instant. (What I mean is . . . if the rifle fires into the side of a mountain, or off the edge of a cliff, then of course they don't hit the ground at the same time. The point is that both the dropped bullet and the fired bullet fall the same vertical distance in the same amount of time, regardless of the big difference in their horizontal speeds.)
the bigger the animal the bigger the caliber of rifle and the heavier the bullet i.e deer 150 grain bullet 243 caliber and up moose 30-06 180 grain and up for both
If you were to drop a bullet at the same moment the rifle bullet is fired, both ought to strike the ground simultaneously. The reason is because the downward force of gravity acts the same on each, whereas a bullet fired towards the ground would enjoy an initial velocity boost, and one fired above the horizontal would begin with a negative velocity.
Both objects accelerate, however due to Newton's 2nd law the acceleration of the rifle is less due to it's higher mass. Newton's second law F = ma In your question the force (F) would be the same on both objects, but the mass (m) would be different and give a different answer for acceleration (a). This difference can be seen by looking at the effect of being on opposite sides of the rifle (ie kickback vs bullet hole)
They will arrive at the floor together (assuming the floor is horizontal). The reason is that both the initial vertical component of the speed, and the vertical acceleration, are the same.
no! The 44special cartridge is based on a bullet of .429-430 in diameter.The 44-40 cartridge is based on a bullet diameter of .427.The chamber dimensions are entirely different for both cartridges also.
Let's begin by defining some terms. The BULLET is the projectile that is fired from a rifle. It is part of the cartridge- along with the cartridge case, powder and primer. When a CARTRIDGE is fired, the firing pin strikes and pinches the rim, causing the primer (a sensitive explosive) to detonate. This produces a flash of heat that ignites the gunpowder. The rapidly burning gunpowder produces hot, expanding gasses. Those gasses push against the base of the lead bullet, and very rapidly accelerate the bullet to about 1400 feet per second. As the bullet is forced into the barrel, it is squeezed into the rifling (spiral grooves cut inside the barrel). That rifling causes the bullet to spin very rapidly, improving the accuracy. The bullet gains heat both from the hot gasses, and from friction with the barrel of the rifle. Just as the bullet is pushed forward, the rifle will also be pushed backwards by an equal force. Known as recoil, or "kick", it demonstrates the physical law of every action having an equal and opposite reaction.