Distance of fall in T seconds = 1/2 g T2
Distance of fall in 2 seconds = (1/2) (9.8) (2)2 = (4.9 x 4) = 19.6 meters
Height of this particular ball after 2 seconds = (70 - 19.6) = 50.4 meters
64 seconds
two and a half seconds
2,580 seconds exactly.
Exactly 30 seconds
There are 151200 seconds in 42 hours.
40.81632653 or (rounded to the nearest 10th) 40.8 seconds
The duration of Initial D is 3300.0 seconds.
64 seconds
A ball thrown vertically upward returns to the starting point in 8 seconds.-- Its velocity was upward for 4 seconds and downward for the other 4 seconds.-- Its velocity was zero at the turning point, exactly 4 seconds after leaving the hand.-- During the first 4 seconds, gravitational acceleration reduced the magnitude of its upward velocity by(9.8 meters/second2) x (4 seconds) = 39.2 meters per second-- So that had to be the magnitude of its initial upward velocity.
two and a half seconds
Exactly 30 seconds
2,580 seconds exactly.
The initial explosion is over in seconds
36 seconds
There are 151200 seconds in 42 hours.
30 seconds: exactly as in the question.
40 seconds