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Ted is 6 years old. Deanna is 41 (6 X 6 = 36 + 5 = 41). 41+6 = 47.

Algebraically, it is fairly simple

Let t = Ted's age, then Deanna's age is 6t + 5

t + (6t + 5) = 47

7t + 5 = 47

7t = 42

t = 6

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Q: Deanna is five years more than six times as old as Ted and the sum of their ages is 47 How old is Ted?
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