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Q: Delta H equals delta E plus delta nRT prove?
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Is this what you were after::::::First we calculate the discriminant, delta, using the formula:delta = b2 - 4*a*cIn our case, delta = 72 - 4*6*(-3) = 121Delta is greater than 0 which means that we have two distinct real solutions x1 & x2.x1 is calculated using the formula:x1 = (-b + sqrt(delta))/2aSimilarly , where 'sqrt(delta)' is the square root of delta.x2 = (-b - sqrt(delta))/2aIn our case sqrt(delta) = sqrt(121) = 11So, for our equation, 6*x2 + 7*x + (-3) = 0, the solutions are:x1 = (-7 + 11)/(2*6) = 0.333333333333x2 = (-7 - 11)/(2*6) = -1.5EquationDeltaX1X26*x2 + 7*x + (-3) = 01210.333333333333-1.5


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