Power: 300 W
Time: 5 h/day * 30 days = 150 h
Energy = Power * Time = 300 * 150 = 45000 Kilowatt Hours
If you want the answer in J:
45000 Kw.H * 3600000 J/(Kw.H) = 162000000000 J = 162 GJ = 0.162 TJ
1500 watt hours
You can buy a volt meter, which can calculate how much electricity is passing through the wires.
100 watts × 10 hours = 1000 watt hours = 1 kilowatt hour (= 1 kwh) = 1 unit of electricity.
A 48 watt appliacne would use 48 x 24 or 1152 watt hours, or 1.152 kilowatt hours in one day.
An electricity meter
Energy = power x time. Convert the numbers into compatible units, and multiply. If you multiply watts x seconds, the answer will be in joules. If you multiply kilowatts x hours, the answer will be in kilowatt-hours.
At Your Service Appliance Repair's hours vary depending on which store is contacted. In general, their hours are from 7 am to 6 pm on the weekdays and 7 am to 5 pm on the weekends.
If I understood your question correctly, 'If you know the power rating of an appliance and the voltage of the line it is attached to, can you calculate the current used by the appliance?' You are looking for this equation: I = Current (Amps) P = Power Rating (Watts) V = Voltage (Volts) I = P/V This equation is useful when calculating the fuse rating for an appliance. For example, and appliance rated at 2400 watts, supplied with 240 volts has a 10 amp maximum. I = 2400/240 however, when it comes to paying for electricity, the energy is measured in units, which can be found using the equation: P = Power (kW) t = Time (Hours) Energy Used (Units) = Pt for example, an appliance rated at 2 kW used for 3 hours, uses 6 units of energy. Units = 2*3
watt denotes the measure of energy consumes per unit time( 1 second). As 1 hp=.746KW so in 24 hours 0.746 KW will be consumed constantly.
Standing charge per quarter ( 3 months) + charge for power consumed (kW - hours) during the quarter. Charge per kW - hour will be shown on the previous bill.
on average how many kilowatts does a house use per day in electricity / gasAnswerA kilowatt is a unit of power, which is the rate at which you consume energy. The amount of energy consumed is expressed in kilowatt hours. So your question should read: "How many kilowatt hours of energy does the average home consume over the period of an hour?" As expressed, your question is meaningless, because you do not 'use' kilowatts.The answer is difficult, because it depends on the size of your house, the number of occupants, where you live (cold vs hot climate), the type of appliances you use -e.g. air conditioning, central heating, etc. If you think that your home is typical, check out your electricity bill -it will tell you have many kilowatt hours you've consumed over the billing period. It's then a case of simple mathematics to determine how many kilowatt hours you consumed over one hour.
All appliances and devices are rated in wattage. The wattage is derived from multiplying the source voltage times the amount of amperage that the appliance draws. The amperage drawn is governed by the internal resistance or impedance that the appliance or device has.Electricity is sold by the utility companies by the kW hour. In other words how many 1000 watts does the appliance use in an hour. For example if a clothes dryer is rated at 4000 watts (or 4 kW) and operates for one hour exactly, your use would be 4 kw hours. This amount of use is registered on the watt meter that is on the side of your home.The utility company has a specific monetary value that it charges for each kW/hr that you use, or as you put it "electricity used". Where I live the charge is .09 cents a kW hour.So to say that an appliance "uses up electricity" is really a misnomer as nothing is used up. The voltage potential remains the same along with the constant draw in amperage due to the resistance of the appliance. You are only charged for the use of the electrical service when the device or appliance is in operation.