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Speed of electron as compared to speed of light is: n = 15% c = 299792458 [m/s]

v = c*n/100 = 4.5 *10^7 [m/s]

So corresponding wavelength as given by the de Broglie equation: h - Planck's constant, m0 - the mass of the electron at zero velocity;

lambda = h/p = h/(v*m0) = 6.62606876*10^-34/(4.5 *10^7*9.10938188*10^-31) = 1.61642*10^-11 [m] = 0.16 [angstroms]

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16y ago
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5mo ago

To determine the wavelength of an electron with a velocity of 15.0 times the speed of light, you can use the de Broglie wavelength formula: λ = h / (m*v), where λ is the wavelength, h is the Planck constant, m is the mass of the electron, and v is the velocity. Plugging in the values (mass of electron, velocity), you can calculate the wavelength of the electron.

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Q: Determine wavelength for electron having velocity 15.0 the speed of light?
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