You have a total of 12 counters arranged on three rows - one counter on each of the same coloured squares.
O O O O
..O O O O
O O O O
Like that.
24 pieces (12 of each color, 3 rows of 4 on each side of the board)
The chekerboard and chessboard are 8 rows long, 8 columns wide, and marked off in 64 squares.
2 rows of 24 3 rows of 16 4 rows of 12
1 row of 12 12 rows of 1 3 rows of 4 4 rows of 3 2 rows of 6 6 rows of 2
Technically, this is impossible as two checkers will always lie in a row. However, how about like this: ................... . @ ............. ..@ @ ......... ..@ ... @ ..... ..@ @ @ @ . ................... (@ = checker) (. = table top, used to ensure picture stays as designed)
The first matrix has 3 rows and 2 columns, the second matrix has 2 rows and 3 columns. Two matrices can only be multiplied together if the number of columns in the first matrix is equal to the number of rows in the second matrix. In the example shown there are 3 rows in the first matrix and 3 columns in the second matrix. And also 2 columns in the first and 2 rows in the second. Multiplication of the two matrices is therefore possible.
Full outer join will fetch at maximum 'addition of 2 tables' Ex: Table A - 2 rows; Table B - 3 rows. Full outer join will fetch in 2+3 = 5 rows. Where as in Cartesian product will fetch in 'product of 2 tables'. Ex: Table A - 2 rows; Table B - 3 rows. Full outer join will fetch in 2x3 = 6 rows
4 Even rows, you'd end up with 2 rows of 3, and another 2 of 2.
Four ways:1 row with 6 in each row.2 rows with 3 in each row.3 rows with 2 in each row.6 rows with 1 in each row.
There are eight possible combinations... 1 row of 24 cans 2 rows of 12 cans 3 rows 8 cans 4 rows of 6 cans 6 rows of 4 cans 8 rows of 3 cans 12 rows of 2 cans 24 rows of 1 can
2-3
The number of rows and the number of chars in that row give you the factor pairs of 18. If you list the number of rows when the 18 chairs can be arranged in rows with an equal number in each row, then this list is the factors of 18. 18 chairs can only be arranged in: 1 row of 18 chairs (1 × 18 = 18) 2 rows of 9 chairs (2 × 9 = 18) 3 rows of 6 chairs (3 × 6 = 18) 6 rows of 3 chairs (6 × 3 = 18) 9 rows of 2 chairs (9 × 2 = 18) 18 rows of 1 chair (18 × 1 = 18) The factors of 18 are thus: 1, 2, 3, 6, 9, 18.