Yes. Of course, the ground exerts an equal-abd-opposite compressive force on you.
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Answer #2:
Experiment:
-- Place a raw egg between the ground and your foot.
-- What did you observe ? Was there any evidence
of a compressive force anywhere ?
Your feet exert a force on the ground so in return the ground exerts a force on your feet.
Yes
a 70kg anything on the earth surface, that isn't subject to buoyancy, will exert 70kg times 9.8m/s/s newtons = 686 this is assuming his feet aren't touching the ground and his whole weight is supported by the chair of course.
That depends on a few things. First, exert on what? The ground? Is the ground made of concrete? Grass? Soft dirt or mud? The reason that is important is we need to know how quickly the 200-pound object stopped in order to answer your question. How far did it sink into the ground? An inch? A half inch? Just 0.1 inch? Second, we need to know whether the object rebounded. Did it just go plop and sink into the ground, or did the object bounce back up like a rubber ball? Those two things will affect the answer. The force exerted is much greater if the object rebounds, but let us assume the object does NOT rebound. The object's kinetic energy (KE) just before hitting the ground is equal to the potential energy (PE) it had at two feet off the ground. Since PE = wh = 200 (pounds force) x 2 feet = 400 foot pounds, we can say that KE is 400 foot pounds right before impact. We know that energy is the ability to do work, and that work is force times distance (W = Fd), so we can write F = W/d. Just before impact, KE is 400 foot pounds, and after impact KE is zero. The change in KE, therefore, is 400 foot pounds. Now, let us assume the object sinks into the ground one inch, which is equal to 1/12 foot (because there are 12 inches to the foot). Hence, the force applied to the object -- or the force exerted by the object -- is 400 / (1/12) = 400 * 12 = 4800 pounds force. What if the object fell on concrete and sunk into it only one tenth of an inch? In that case the force exerted would be 400 / (0.1/12) = 48,000 pounds force, which equals 24 tons!
The answer cannot be uniquely determined from the information given.There are at least two problems with the question:1. It doesn't matter how much your feet move, what matters is how much your center of mass moves.2. The force required depends on how much you weigh.
Your feet exert a force on the ground so in return the ground exerts a force on your feet.
the concept's application here is very simple. As we walk we exert a certain amount of force on the Earth and governed by the 3rd law the Earth exerts the equal amount of force back on our foot (opposite direction) but as the Earth is very massive to observe the push that we exert only the force the it exerts it felt this added to friction provides the stability of the feet while in movement
Because your feet are not accelerating, the force exerted by the floor upon your feet must be exactly the same as the force exerted by your feet on the floor. If you are standing, the amount of force exerted by your feet, and thus the amount of force exerted by the floor, is equivalent to your weight.
Yes, the force exerted by the floor on our feet is equal to the force that our feet exerted on the floor, or it just depends on your weight, If you are heavier than the normal. When you stand, the longer the time you stand, the more pain you feel on your feet. And we can't be move upward by the force that the floor exerted on our feet because of the force of our weight that keeps us on the ground, and also because of gravity.
Yes
Yes
The floor is a stationary object (in relationship to you). The floor will provide only enough force to match the force of gravity holding you down. It has to be equal.
Teflon, Ice or an oiled surface.
When you jump, you exert a force greater than the force of gravity to achieve a net positive upward acceleration - at least until your feet leave the ground and you quit exerting force. The net upward force is Fnet = (force you push off with) - (force of gravity) Because the moon has less mass than the earth, the force of gravity is less. As a result, the force you exert to jump on earth would give a higher net upward acceleration on the moon and allow you jump higher.
Sand is made up of fine particles so there are spaces between the particles so as run your feet push on the ground, however unlike on normal ground some of force you exert to push yourself forward is used to compress the sand particles closer together so you require more force to compensate to move forward as the reaction force is lower in proportion.
a 70kg anything on the earth surface, that isn't subject to buoyancy, will exert 70kg times 9.8m/s/s newtons = 686 this is assuming his feet aren't touching the ground and his whole weight is supported by the chair of course.
You are able to jump by using your feet to apply force to the ground and then using this force to allow you to lift off the ground.