Yes.
Every body that is falling, (if there is no other force then the gravity force) will fall in constant acceleration.
Mass does not affect the acceleration of the body.
According to Newton's second law:
F=m*a
m*g=m*a
g=a
F= Force
m= mass
a= acceleration
g= gravity acceleration
m*g= the force of gravity
A falling rock in vacuum accelerates at 9.8 meters per second2 ... the acceleration of gravity at the earth's surface.A falling rock in air has a smaller acceleration than in vacuum, because of air resistance;the exact figure depends on the rock's weight and shape.A falling rock in water has an even smaller acceleration than it air, because of water resistance; the exact figure again depends on the rock's weight and shape.
The acceleration of gravity is 9.8 meters/sec2.In 1.5 seconds after it's dropped, any object is falling at (9.8 x 2) = 19.6 meters/sec.The mass of the rock makes no difference.
Any object moving under the influence of gravity only and no other outside forces has a constant acceleration of 9.8 meters (32.2 feet) per second2, directed down.The speed changes. The acceleration doesn't, regardless of the angle, speed, trajectory, color, temperature, cost, size, mass, or weight of the falling object.
A rock that is sitting on top of a cliff has what is called potential energy.
1,100 j 110 j
2:1
yes
Weathering makes rocks at the top of a cliff suddenly fall.
A rock falling of a cliff.
I consider that this is a physical process.
A falling rock in vacuum accelerates at 9.8 meters per second2 ... the acceleration of gravity at the earth's surface.A falling rock in air has a smaller acceleration than in vacuum, because of air resistance;the exact figure depends on the rock's weight and shape.A falling rock in water has an even smaller acceleration than it air, because of water resistance; the exact figure again depends on the rock's weight and shape.
chemical ----------- I consider that this is a physical process.
The acceleration of gravity is 9.8 meters/sec2.In 1.5 seconds after it's dropped, any object is falling at (9.8 x 2) = 19.6 meters/sec.The mass of the rock makes no difference.
speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s
Since there is no air, there is no air resistance so acceleration of free-fall is constant throughout the fall. Thus the first of the four equations of motion can be used.v = u + atwhere v = final velocity, u = initial velocity, a = constant acceleration, t = time of motionv = 0 + (9.8 m/sec/sec)(2 sec) = 19.6 meters per second.---Speed = (acceleration) x (time)Acceleration of a dropped rock = gravity = 9.8 m/s2Speed = (9.8) x (2) = 19.6 m/sec
The distance covered during time ' T ' seconds under constant acceleration isD = V0T + 1/2 A T2D = the distanceV0 = speed at the beginning of the time TA = acceleration during the time TIn this question, V0 = 0, T = 1.895, and A = acceleration of gravity = 9.8 m/s2.D = 0 + (1/2) (9.8) (1.895)2 = 17.6 meters (57.8 feet) (rounded)
No effect whatsoever. Without air to interfere with the effects of gravity, a small feather and a large rock fall with the same acceleration.