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Yes.

Every body that is falling, (if there is no other force then the gravity force) will fall in constant acceleration.

Mass does not affect the acceleration of the body.

According to Newton's second law:

F=m*a

m*g=m*a

g=a

F= Force

m= mass

a= acceleration

g= gravity acceleration

m*g= the force of gravity

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Q: Does a rock falling from a cliff have a constant acceleration?
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Related questions

What it the ratio of the acceleration due to gravity of a 2kg falling rock compared to the acceleration due to gravity of a 1kg falling rock?

2:1


Is a large rock falling from a cliff and breaking mechanical?

yes


What is a rock at the top of a cliff that suddenly falls?

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What is an example of how potential energy can transform into kinetic energy?

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Is a small rock falling of a cliff chemical or weathering?

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How fast does a rock fall in the ocean?

A falling rock in vacuum accelerates at 9.8 meters per second2 ... the acceleration of gravity at the earth's surface.A falling rock in air has a smaller acceleration than in vacuum, because of air resistance;the exact figure depends on the rock's weight and shape.A falling rock in water has an even smaller acceleration than it air, because of water resistance; the exact figure again depends on the rock's weight and shape.


Is a small rock falling off a cliff mechanical or chemical?

chemical ----------- I consider that this is a physical process.


A 12 kg rock falls from rest off a cliff and hits the ground in 1.5 s What is the velocity?

The acceleration of gravity is 9.8 meters/sec2.In 1.5 seconds after it's dropped, any object is falling at (9.8 x 2) = 19.6 meters/sec.The mass of the rock makes no difference.


If a Rock is dropped off a cliff with an initial speed of 0 ms What is the rock's speed after 3 seconds in ms if it encounters no air resistance?

speed is decided by v = a(t), where t is your time variable and a is your acceleration constant. after 3 seconds, your velocity v = (9.8m/s2)(3s) = 29.4m/s


If a rock on Earth is dropped in a vacuum and has an initial speed of 0 meters per second What is the rock's falling speed after 2 seconds?

Since there is no air, there is no air resistance so acceleration of free-fall is constant throughout the fall. Thus the first of the four equations of motion can be used.v = u + atwhere v = final velocity, u = initial velocity, a = constant acceleration, t = time of motionv = 0 + (9.8 m/sec/sec)(2 sec) = 19.6 meters per second.---Speed = (acceleration) x (time)Acceleration of a dropped rock = gravity = 9.8 m/s2Speed = (9.8) x (2) = 19.6 m/sec


A girl drops a rock from the edge of a cliff and observes that it strikes the bottom 1.895 s later How high is the cliff?

The distance covered during time ' T ' seconds under constant acceleration isD = V0T + 1/2 A T2D = the distanceV0 = speed at the beginning of the time TA = acceleration during the time TIn this question, V0 = 0, T = 1.895, and A = acceleration of gravity = 9.8 m/s2.D = 0 + (1/2) (9.8) (1.895)2 = 17.6 meters (57.8 feet) (rounded)


What is the effect of mass of freely falling body on the gravitational acceleration?

No effect whatsoever. Without air to interfere with the effects of gravity, a small feather and a large rock fall with the same acceleration.