The largest variation from two objects moving downward either 'dropped' or 'thrown' thereby allowing earth's natural gravity to increase until an object approaches and/or reaches maximum velocity. The difference in the two examples, 'dropped' or 'thrown' objects merely illustrates that the "thrown" object will reach maximum velocity quicker than the 'dropped' object.
Yes. "Violently" simply means that the object has a large initial downward velocity.
Its vertical speed after time 't' is still V0+gt, just as if it were gently dropped and V0=0.
Yes it does. The object's acceleration is still 9.8 meters per second2 downward,
regardless of its initial velocity up, down, or sideways.
The magnitude of the velocity will increase. The velocity will be downward - and since it increases, the acceleration will be downward. The acceleration doesn't change (it will remain constant at about 9.8 m/sec2), unless air resistance becomes significant.
Weight is felt by the body resisting the pull (acceleration) of gravity. Less acceleration means less pull thus less weight. The rate at which you are accelerating downward subtracts from the pull of gravity, thus your weight is less. If you fall, say from a cliff or tall building you accelerate downward at exactly the acceleration of gravity so you're completely weightless.
Yes.
At terminal velocity (constant velocity), the acceleration is zero, but prior to that, there is a downward acceleration.
Horizontal . . . acceleration is zero, speed is constant Vertical . . . acceleration is 'G' downward, speed constantly increases downward
No. Regardless of its initial speed, the object still experiences downward acceleration at the rate of 'G'.
The magnitude of the velocity will increase. The velocity will be downward - and since it increases, the acceleration will be downward. The acceleration doesn't change (it will remain constant at about 9.8 m/sec2), unless air resistance becomes significant.
If it is gravitational acceleration then it it is positive in downward and negative in upward direction..if it is not gravitational acceleration then it is depending upon the value of acceleration.
Weight is felt by the body resisting the pull (acceleration) of gravity. Less acceleration means less pull thus less weight. The rate at which you are accelerating downward subtracts from the pull of gravity, thus your weight is less. If you fall, say from a cliff or tall building you accelerate downward at exactly the acceleration of gravity so you're completely weightless.
Yes.
At terminal velocity (constant velocity), the acceleration is zero, but prior to that, there is a downward acceleration.
Horizontal . . . acceleration is zero, speed is constant Vertical . . . acceleration is 'G' downward, speed constantly increases downward
9.8 meters per seconds squared in the downward direction.
acceleration of a falling body is 9.8m/s*s and its direction is vertically downward.
Sure. Anything you toss with your hand has constant acceleration after you toss it ... the acceleration of gravity, directed downward. If you toss it upward, it starts out with upward velocity, which reverses and eventually becomes downward velocity.
Then - according to Newton's Second Law - you would have more acceleration downward.
The acceleration of a falling object is called gravity. A free-falling object has an acceleration of 9.8 m/s/s when going downward on Earth.