Density is independent of the amount of material in a sample. A sample of a homogeneous substance used to find the density can have any volume. If a cm3 of the substance weighs 8.1 grams, then 10 cm3 will weigh 81.0 grams.
We might consider water in a glass or bottle as an example. A small sample will have a given weight (mass) because water has a given density. Ten times that sample volume will have ten times the mass of that volume of water. The density of water does not change if we examine water in a small glass and another sample of the same water in a gallon jug.
You have to know two out of three ... mass, volume, density ... then you can find the missing one. If density is missing . . . Density = (mass)/(volume) If mass is missing . . . Mass = (density) x (volume) If volume is missing . . . Volume = (mass)/(density)
yes because the quota sample include the random sample and when we have over estimation we will use the quota sample
larger is the wrong word to use here as it would depend on density, kg is a unit of weight not size. 1kg is certainly greater than 1g assuming the two substances are the same. but it is wrong to use the word larger in this question.
8.57 g D=mass/volume Wanting to fight weight of the vial so you would use Mass=density*volume 8.6mL is volume .997g/mL is density
Basically you need more information. You can use the following formulae: density = mass / volume weight = mass x gravity
density = mass / volume
This depends on the nature and form of the sample:- for a solid with a regulate shape weight the sample and calculate the volume from the dimensions; density is the ratio between mass and volume. You can measure the volume of great sample by water displacement.- for other solids use a pycnometer- for liquids use a densimeter (simple or electronic)etc.
You have to know two out of three ... mass, volume, density ... then you can find the missing one. If density is missing . . . Density = (mass)/(volume) If mass is missing . . . Mass = (density) x (volume) If volume is missing . . . Volume = (mass)/(density)
table 3.7 in prentice hall chemistry That's going to depend on the pressure of the sample as well as its temperature.
737.22 kg/m^3 The density depends on a whole range of factors including purity and Temperature. Use the above as a guide though but in situations where the value of density is critical, take a sample to the lab for them to determine the correct value.
"This is a sample of how to use the word 'sample' in a sentence."
It depend on the environmrnt.
This depends on the nature and form of the sample:- for a solid with a regulate shape weight the sample and calculate the volume from the dimensions; density is the ratio between mass and volume. You can measure the volume of great sample by water displacement.- for other solids use a pycnometer- for liquids use a densimeter (simple or electronic)etc.
The simplest way is to use the formula: P = m / V Density = mass / volume So to calculate the denisty of the rock you will have to find out how much it weighs and how much volume it occupies. You can measure the weight by placing the rock on a weighing scale, this will give the weight in grams. You can determine the volume by submerging the rock in a measuring cup partially filled with water and measuring how much the volume increases. This will give the volume in cm3 Now use the formula to calculate its density in g/cm3.
Gerald S. Strickler has written: 'Use of the densiometer to estimate density of forest canopy on permanent sample plots' -- subject(s): Density, Densitometry, Forest canopies, Measurement
well density measures how much an object is by its size and you calculate it by finding the mass then volume.Then you divide the two answers then whatever answer you get,you round it to the nearest tenths
No, to tell how hard a mineral is you either have to test it or determine what mineral it is. Testing uses materials of known hardness such as a fingernail, or copper penny, or scratch plate, if the mineral is scratched by whatever you use to test it is softer. Hardness however is not based on size it will be the same for any sample of the same rock no matter what the size because its based on atomic arrangement and bond type.