Currently, Amy is 12 years old when Emily is 4.
In 4 years time, Amy will be 16, and Emily will be 8.
---
Solve using the algebraic expression for the number of years x :
12 + x = 2 (4 + x)
12 + x = 8 + 2x
4 + x = 2x
4 = x
12 + 4 = 16, 4 + 4 = 8
16
20
Amy will be 16 when she is twice as old as Emily at 8.
Zoron will be seventeen and his sister will be seven
Mike is 12. Mary is 4. In 4 years, Mike will be 16 and Mary will be 8. So Mike will be twice as old as she is in four years.
three times a number decreased by eleven
Twice with a remainder of three
Amy will be 16 when she is twice as old as Emily at 8.
Mary is dead
Turning this into equations we get :E = current age of EmilyS = current age of SamanthaE = 3S (Currently, Emily is 3 times as old as Samantha)E + 6 = 2*(S + 6) (In 6 years, Emily will be twice as old as Samantha)Solving for E and S, we get that cuurently, Samantha is 6 and Emily is 18(6 * 3 = 18). and in 6 years Samantha would be 12 and Emily would be 24, making Emily twice as old as Samantha (12 * 2 = 24)
12,4...16,8
Mary is 4 years old. [A+]
twice the difference of three times a number and eight
Sister = 5 David = 13
Zoron will be seventeen and his sister will be seven
There are two possible (and different) answers: 2x + 3y = 12 or 2*(x + 3y)= 12 The first one is (twice a number) increased by (three times another) The second is twice (a number increased by (three times another)).
0.4286 times.
She had three children and got married twice.
The AED may shock once, twice, or three times.