Metal and Alloys

# Equation for oxalic acid and potassium hydroxide?

H2C2O4 + 2KOH --> K2C2O4 + 2H2O

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## Related Questions

The equation for hydrobromic acid and potassium hydroxide is as follows: HBr + KOH --&gt; HOH + KBr

Equation: H2SO4 + 2KOH = K2SO4 + 2H2O In words: Sulphuric acid and potassium hydroxide yield potassium sulfate and water.

Nitric acid and potassium hydroxide react to form waterand potassium nitrate.

Hydrochloric Acid + Potassium Hydroxide = Potassium Chloride + Water HCl + KOH = KCl + H2O

HC2H3O2 + KOH --&gt; KC2H3O2 + H2O Acetic Acid + Potassium Hydroxide --&gt; Potassium Acetate + Water.

Hydrocloric acid plus potassium hydroxide makes potassium chloride plus water.

Oxalic acid + Sodium Hydroxide ----> Sodium Oxalate + WaterH2C2O4 + 2 NaOH ----> Na2C2O4 + 2 H2O

The net ionic equation for potassium hydroxide and phosphoric acid should look like the following: H3PO4 + 3OH- --&gt; PO4^3- + 3HOH(l).

KOH + HClO2 --> KClO2 + H2Oalkali + acid --> salt (potassium chlorite; not chloride!) + water

the balanced symbol equation for nitric acid and sodium hydroxideis as follows :potassium hydroxide + nitric acid &Atilde;&cent;&acirc;&euro;&nbsp;&acirc;&euro;&trade; potassium nitrate + water.KOH + HNO3 &Atilde;&cent;&acirc;&euro;&nbsp;&acirc;&euro;&trade; KNO3 + H2O

the chemical equation for Sulphuric acid neutralises potassium hydroxide giving water and a salt called potassium sulphate is represnted below.Sulfuric Acid and Potassium Hydroxide neutralize each other in the following reaction:H2SO4+2KOH&acirc;&dagger;&rsquo;K2SO4+2H2O.. H2SO4+2KOH&acirc;&dagger;&rsquo;K2SO4+2.

KOH + HCl &rarr; H2O + KCl Potassium hydroxide will react with hydrochlric acid to produce an insoluble precipitate, potassium chloride, as well as water. This is a strongly exothermic reaction.

Potassium hydroxide + sulphuric acid = Potassium sulphate + water

C2H2O4 + 2NaOH -->> C2O4Na2 +2H2OOxalic acid + Sodium hydroxide -->> sodium oxalate+ waterB.Cu + 2NO3- + 4H+ &rarr; Cu2+ + 2NO2 + 2H2O