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Answered 2009-04-21 01:41:27

H2C2O4 + 2KOH --> K2C2O4 + 2H2O

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The chemical equation is: C2H2O4 + 2 KOH = C2K2O4 + 2 H2O


potassium hydroxide is POH and nitric acid is HNO3


Hydrochloric Acid + Potassium Hydroxide = Potassium Chloride + Water


The equation for hydrobromic acid and potassium hydroxide is as follows: HBr + KOH --> HOH + KBr


potassium hydroxide + sulphuric acid -> potassium sulphate + water



Equation: H2SO4 + 2KOH = K2SO4 + 2H2O In words: Sulphuric acid and potassium hydroxide yield potassium sulfate and water.


Nitric acid and potassium hydroxide react to form waterand potassium nitrate.


Hydrochloric Acid + Potassium Hydroxide = Potassium Chloride + Water HCl + KOH = KCl + H2O


HC2H3O2 + KOH --> KC2H3O2 + H2O Acetic Acid + Potassium Hydroxide --> Potassium Acetate + Water.


Hydrocloric acid plus potassium hydroxide makes potassium chloride plus water.


Oxalic acid + Sodium Hydroxide ----> Sodium Oxalate + WaterH2C2O4 + 2 NaOH ----> Na2C2O4 + 2 H2O



The net ionic equation for potassium hydroxide and phosphoric acid should look like the following: H3PO4 + 3OH- --> PO4^3- + 3HOH(l).



KOH + HClO2 --> KClO2 + H2Oalkali + acid --> salt (potassium chlorite; not chloride!) + water


the balanced symbol equation for nitric acid and sodium hydroxideis as follows :potassium hydroxide + nitric acid → potassium nitrate + water.KOH + HNO3 → KNO3 + H2O


the chemical equation for Sulphuric acid neutralises potassium hydroxide giving water and a salt called potassium sulphate is represnted below.Sulfuric Acid and Potassium Hydroxide neutralize each other in the following reaction:H2SO4+2KOH→K2SO4+2H2O.. H2SO4+2KOH→K2SO4+2.




(COOH)2 + CaCl2 + 2NH4OH ----> CaC2CO4 + 2NH4Cl + 2H2O


KOH + HCl → H2O + KCl Potassium hydroxide will react with hydrochlric acid to produce an insoluble precipitate, potassium chloride, as well as water. This is a strongly exothermic reaction.


Potassium hydroxide + sulphuric acid = Potassium sulphate + water


C2H2O4 + 2NaOH -->> C2O4Na2 +2H2OOxalic acid + Sodium hydroxide -->> sodium oxalate+ waterB.Cu + 2NO3- + 4H+ → Cu2+ + 2NO2 + 2H2O