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Explain how you can break numbers apart to find the product 812?
Wiki User
∙ 14y ago
812 !!!
You inspect the number;
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If it is an EVEN number it will divide by '2'
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If it ends in '5' or '0' it will divide by '5'
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If the digits sum to '9' , then it will divide by '9'
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Without any of the above, try dividing by either '3' or '7'.
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If none of the above work, keep trying by dividing by prime numbers; 11,13,17,19,23,29, etc.,
For 812 . It is an even number so it will divide by '2'
It does not end in '5' or '0' so will NOT divide by '5'
Its digits 8+1+2 = 11 Do not sum to '9' so will NOT divide by '9'.
So
2)812 = 406
2)406 = 203
'203' is an ODD number so will not divide by '2' . Since it does not end in '5' ot will not divide by '5' . It digits do NOT sum to '9' so will not divide by '9'.
So try '3'
3)203 = 67 remainder '2' Does not divide by '3'
So try '7'
7)203 = 29
So there you have it . 812 breaks down to 2,2,7,& 29. the factors.
When multiplied together 2 x 2 x 7 x 29 = 812 or 4x7 x 29 = 812 or 28 xx 29 = 812
lenpollock
Wiki User
∙ 14y ago812 = 2 * 2 * 7 * 29
Start dividing the number with any of the prime numbers that divide it properly and continue dividing until you are left with a reminder of 0 or a Prime number.
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