If We are looking for A, B and C
If the first number is A
then we know
B = A+2
C = A+4
and
3A = B+C
or
3A = (A+2) + (A+4)
so
3A = 2A +6
3A - 2A = 6
A = 6
B= 8
C= 10
Their sum is 99.
-7
18, 20 and 22
its 4 cuz the first is 0 second is 2 third is 4
3X + 6 First Number = X Second Number = X + 2 Third Number = X + 4 Sum of all three numbers = X + X + 2 + X + 4 = 3X + 6
Their sum is 99.
1, 2 and 3 -1, -2, and -3 6 or -6
1349
-7
The third number is 112, the numbers are 86, 86, 112, 172
18, 20 and 22
its 4 cuz the first is 0 second is 2 third is 4
If the first number is 915, then the second will be 915 + 1 = 916 and the third number will be 915 + 2 = 917. Add 915, 916 and 917 to find the sum. If the question is, what are the three consecutive numbers whose sum is 915, then divide 915 by 3 to find the middle number which is 305. Since the consecutive numbers differ by 1, the numbers are 304, 305, and 306.
74658
3X + 6 First Number = X Second Number = X + 2 Third Number = X + 4 Sum of all three numbers = X + X + 2 + X + 4 = 3X + 6
First of all, let's set up the equation.x=the first number=44x+1=the second number=45x+2=the third number=46x+x+1+x+2=1353x+3=1353(x+1)=135x+1=45x=44
If the first of these consecutive integers is x, the second integer would be x + 1, and the third integer would be x + 2.Since the sum of the second and the third integer is 17, we can writex + 1 + x + 2 = 172x + 3 = 172x + 3 - 3 = 17 - 32x = 142x/2 = 14/2x = 7Thus, the consecutive integers are 7, 8, and 9.