Find A and B if 36A2B is a multiple of 9 and a multiple of 4 A does not equal B?
You need to find a product of 9 & 4 which is 36. A2B mean its a 3 digit number that has a 2 in the middle.
Now, you need to multiply 36 by 10 to make it a 3 digit number which give you 360. Since 6 is the middle number and its not 2, then 360 is not right. From this point, you keep adding 360 to to original number which is 360 until you get a number that is divisible by both 4 & 9.
So, 360 + 360 = 720. Here, the 2 is the middle number so this is a good start.
Now, 4 goes into 720 (180 times) and 9 goes into 720 (80 times). So A = 7 and B = 0. The answer is 36720 (this number is divisible by both 4 & 9.
1.take 2 numbers 2.make both the numbers into their smallest dividends (which are equal to the number when multiplied together, the best way to do this is by using a tree diagram) 3.find out the most amount of times each dividends are in one of the numbers that you are going to be finding the lowest common multiple, not the smallest dividends 4.multiply the numbers you got from step 3 for the lcm example: 6…
Assume we want to find the lowest multiple of the numbers. The lowest multiple of the numbers is factored to primes with the maximum exponents. The other way of thinking of the lowest multiple is that these numbers divide the large number in order for the large number to be the lowest multiple. To help us understand how to work out with lowest multiple, let's consider this following example: Find the GCF of 4 and…
Can you always find the least common multiple of two numbers by multiplying them together.why or why not?
You can always find a common multiple of two numbers by multiplying them together; it will not always be the least common multiple. As one counterexample, if one of the numbers is a multiple of the other, the first number is the LCM of the two. 9 x 3 = 27 The LCM of 9 and 3 is 9. 4 x 6 = 24 The LCM of 4 and 6 is 12.
No, but vice versa holds true. Case and point: 6 is a multiple of 2, but not a multiple of 4. 8 is a multiple of 4, and is a multiple of 2. Because a factor of 4 is 2, every multiple of 4 is also a multiple of 2. But since 4 is not a factor of 2, rather, only half of it, only half of the multiples of 2 will be multiples of…