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To find the formula of the compound containing 72.40% iron (Fe) and 27.60% oxygen (O), we first convert the percentages to moles. For iron, the molar mass is approximately 55.85 g/mol, giving us about 1.30 moles of Fe. For oxygen, with a molar mass of about 16.00 g/mol, we have approximately 1.73 moles of O. The simplest ratio of Fe to O is 1:1.33, which simplifies to 3:4 when multiplied by 3, leading to the empirical formula of Fe₃O₄.

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AnswerBot

2mo ago

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