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Bisect two arcs above and below the given points or line and the perpendicular of these arcs cuts through the midpoint.
Draw a line joining a point and its image and find its midpoint. Repeat for another pair of point and its image. The line joining these midpoints is the line of reflection.
This can be done with the equation (x1+x2)/2, (y1+y2)/2 which, when solved, creates a (x,x) solution, or a coordinate pair solution. if you had the points (2,4) and (4,8) you would put x1 (2) plus (+) x2 (4) divided by 2, and 2+4 is 6, and 6/2 is 3, so we know our midpoint x value is 3. Then, we would plug in our 'y' values, so we would have y1 (4) + y2 (8) and 4+8 = 12 and 12/2 is 6, so our solution coordinate ordered pair would be (3,6).
The horizontal distance between them is from -5 to 1, that is 6 units. The vertical distance between them is from 1 to 6, that is 5 units. So, using Pythagoras, the distance between then, along the diagonal, is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) units.
Infinitely many. There are infinitely many points in the plane and although any pair of points define a line, no matter how many lines you are given, it is always possible to find a point that is not on any of them - that is, a point that is not collinear.
Bisect two arcs above and below the given points or line and the perpendicular of these arcs cuts through the midpoint.
You can with a pair of compasses!
Draw a line joining a point and its image and find its midpoint. Repeat for another pair of point and its image. The line joining these midpoints is the line of reflection.
Pentagon GIANT with diagonal AG parallel to side NT
Use the distance formula. SQRT( (y1-y2)^2 + (x1-x2)^2) ) x1 and y1 are the first coordinate pair x2 and y2 are the second coordinate pair
A line segment (sometimes just segment) is a pair of endpoints and all the points on a line between them.
A line segment (sometimes just segment) is a pair of endpoints and all the points on a line between them.
To find the slope between two points: slope = change_in_y/change_in_x Thus for the points (4, 5) and (6, 8), the slope between them is given by: slope = (8-5)/(6-4) = 3/2 = 1½ = 1.5
A line segment (sometimes just segment) is a pair of endpoints and all the points on a line between them.
A line segment (sometimes just segment) is a pair of endpoints and all the points on a line between them.
No
To find the slope of a line, which is m, you can take the difference between the y-values and divide it by the different between the x-values of the two points, in this case are (34,5) and (54,2). So, your slope is equal to (2-5)/(54-34)=-3/20