Let the three numbers in GP: a/r, a, ar---------(A)
Where '^' is power of . . .
Sum of these numbers are:
a/r +a +ar = 38
a(1\r+1+r) = 38 ---- (1)
Product of these numbers are:
a^3 = 1728
= (12)^3
a = 12
Putting the value of a in (1) you will get:
12(1\r+1+r) = 38
And factorising, we get
r = 2/3 or r = 3/2
Sub. the r and a value in (A), we get
8,12,18 or 18,12,8. When a = 12
And smallest no. is 8.
(12)144 = 1728
1728 is a pure number. Without units it has no meaning in volumetric measurements.
It is: 12*12*12 = 1728
1728 is divisible by 6. 1728/6=298A number is divisible by 6 if:The number is evenThe sum of the digits is divisible by three1728 is an even number.1+7+2+8=1818 is divisible by three.Therefore 1728 is divisible by 6.Note: You can also add 1+8=9 to make it simpler to check if it is divisible by 3.
24√3 or 41.5692194 or 41.57, to the justified number of significant digits since 1728 has only four.
the cube root of 1728 is 12
As a product of its prime factors in exponents: 2^6 times 3^3 = 1728
(12)144 = 1728
Ramanujan number is the smallest natural number that can be can be expressed as a sum of two perfect cubes in two different ways:- 123 + 13 = 1728+1 =1729 103 + 93 = 1000+729 =1729
The number 12.
1728 is a pure number. Without units it has no meaning in volumetric measurements.
1728 is even so it cannot have an odd cube root.
1728/60=28 and left 48number is written as 28,48
It is: 12*12*12 = 1728
3√1728 = 12
1728 is divisible by 6. 1728/6=298A number is divisible by 6 if:The number is evenThe sum of the digits is divisible by three1728 is an even number.1+7+2+8=1818 is divisible by three.Therefore 1728 is divisible by 6.Note: You can also add 1+8=9 to make it simpler to check if it is divisible by 3.
24√3 or 41.5692194 or 41.57, to the justified number of significant digits since 1728 has only four.