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Formula for Heat loss in a pipe?


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Answered 2009-04-16 07:40:49

pips are generally cylindrical in structure of amount of heat loss through pipe is given by the formula Q= 2 pi k L(T1-T2)/ln(r2/r1) where k=conductivity of material of which pipe is made T1= temperature of inside layer pipe T2=temperature outside layer of pipe L= length of pipe r1= inner radius r2=outer radius ln=natural logrithem pi=22/7 the above condition applies for steady state flow,single layer over cylinder and neglecting conductivity convection to take conductivity convection into account term Q* must be added Q*=2 pi L{ r1 hi(Ti-T1)+r2 ho(T2-To)} hi=convective coefficient for inside layer ho=convective coefficient for outside layer Ti= temperature of inside space of pipe To=temperature of outside space of pipe for unsteady condition there is another formulaa

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Insulation slows down the loss of energy (heat flow) from the water in the pipe to the surroundings. It will protect from losing heat by convection (wind moving past the pipe removes heat faster than stationary air). If the temperature is cold enough, for a long enough time, eventually it will freeze, even with insulation.Insulation slows down the loss of energy (heat flow) from the water in the pipe to the surroundings. It will protect from losing heat by convection (wind moving past the pipe removes heat faster than stationary air). If the temperature is cold enough, for a long enough time, eventually it will freeze, even with insulation.


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http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/heatcond.html





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