Using the expression for tangent: tan(angle)=opposite/adjacent,
and x to denote the height of the tree,
we have tan(35)=x/24
So x=24*tan(35) = 24*0.4738 = 11.37
So the tree is 11.37 feet tall
The flagpole is 15.92 metres, approx.
Angle of elevation: tangent angle = opposite/adjacent and by rearranging the given formula will help to solve the problem
WARNING: Do not, under any conditions, look at the sun, directly or indirectly.The find the elevation of the sun, measure the angle that an object's shadow from the sun makes. One way to do this is with a stick in the ground. Assuming the stick is perpendicular to the ground, the ratio of the stick's length to the shadow's length is the tangent of the angle of elevation. Solve for inverse tangent, and you have the angle.
If we assume the the flagpole makes a 90 degree angle with the ground, then the angle of elevator for the sun is 34.778°
Use the tangent ratio: tan = 22.5/34 = 45/68 tan-1(45/68) = 33.49518467 degrees Angle of elevation = 33o29'42.66''
The question is not quite clear but if the angle of elevation is 26 degrees at a distance of 165 feet away from the building then its height is 80.47587711 feet. 165*tan(26) = 80.47587711 feet
Using the sine rules in trigonometry the height of the mountain works out as 3704 meters in height to the nearest whole number.
When the angle of elevation equals 45 degrees. tan-1(1) = 45 degrees.
By drawing a sketch from the given information then using triangulation and trigonometry the height of the mountain works out as 3704.435 meters rounded to three decimal places.
Using tangent ratio for a right angle triangle: tan(48.4)*7.42 = 8.357 m which is the height of the flag pole rounded to 3 decimal places
Tangent of theta = Y/X, or opposite the angle/the adjacent of angle. So; Tangent of 42 degrees = height/80' 80' tan 42 = height = 72 feet ( you might want to subtract that 4.5 foot eye height )
height = 15 ft base = 20 ft angle of elevation = arctan (15/20) = 36.87 degrees
Angle of elevation: tan-1(100/130) = 37.6 degrees rounded to one decimal place
Using the formula: tangent = opposite/adjacent whereas tangent angle = height/ground distance, will help to solve the problem
A simple angle of elevation problem...You want to find out the height of a tree. You measure the distance from you to the base and find that it is 100 feet. You measure the angle of elevation of the top and find that it is 30 degrees. You are six feet tall. How tall is the tree?Answer: The tree is 64 feet tall. Its height is tangent 30 times 100 + 6.
If you are looking for the angle of elevation from the ground to the top of Qutub Minar, here is a solution. Qutub Minar is 72.5 meters tall. The angle of elevation would equal arctan(72.5/5). It comes out to approximately 86.05 degrees.
A girl 1.2 m in height is 25 m away from a tower 18 m high. What value is the angle of elevation of the top of the tower from her eyes?