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Q: How do I make a velocity time graph with only a displacement time graph with no points?
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How to calculate distance from a velocity time graph?

You cannot since the graph shows displacement in the radial direction against time. Information on transverse displacement, and therefore transverse velocity, is not shown. For example, there is no difference in the graph of you're staying still and that of your running around in a circle whose centre is the origin of the graph. In both cases, your displacement from the origin does not change and so the graph is a horizontal line. In the first case the velocity is 0 and in the second it is a constantly changing vector. All that you can find is the component of the velocity in the radial direction and this is the slope of the graph at the point in question.


How do you make an acceleration time graph from the data of a velocity time graph?

take the slope of every change in the velocity time graph and plot it


How do you make a velocity vs time graph from an acceleration vs time graph?

Your acceleration vs. Time graph is the slope of your velocity vs. time graph


Why is the slope of a distance velocity squared graph straight and a distance velocity graph is not?

When acceleration is constant, one equation of kinematics is: (final velocity)^2 = 2(acceleration)(displacement) + (initial velocity)^2. When you are graphing this equation with displacement or position of the x-axis and (final velocity)^2 on the y-axis, the equation becomes: y = 2(acceleration)x + (initial velocity)^2. Since acceleration is constant, and there is only one initial velocity (so initial velocity is also constant), the equation becomes: y = constant*x + constant. This looks strangely like the equation of a line: y = mx + b. Therefore, the slope of a velocity squared - distance graph is constant, or there is a straight line. Now, when you graph a velocity - distance graph, the y axis is only velocity, not velocity squared. So if: v^2 = mx + b. Then: v = sqrt(mx + b). Or: y = sqrt(mx + b). This equation is not a straight line. For example, pretend m = 1 and b = 0. So the equation simplifies to: y = sqrt(x). Now, make a table of values and graph: x | y 1 | 1 4 | 2 9 | 3 etc. When you plot these points, the result is clearly NOT a straight line. Hope this helps!


In a coordinate graph of two related variables when does it make sense to connect the points?

When the data on the graph is continuous,it does make sense to connect the points on the graph of 2 related variables.


How do you find velocity of an object?

Before giving an answer to this question i will like to make note that velocity and speed are two different terms which become same only in case of straight line motion/ 1-D motion. Speed is the rate of change of DISTANCE with respect to time ,while Velocity is the rate of change of DISPLACEMENT with respect to time. Distance is the total path covered by a body between any two points while Displacement is the shortest distance between the two points.... Distance b/w two different points can never be zero or negative will displacement can be zero or negative.


Why make a velocity time graph?

Because its really fun :)


How is deceleration represented on a velocity per time graph?

It is radial the velocity in a direction towards or away from a fixed point of reference (the origin) at a given time. The velocity time graph takes no account of motion in a direction across the radial direction.


Is displacement calculated as velocity x time?

Yes, you see as Velocity = Displacement/Time, To get displacement by its self, we need to get the 1/time over to the other side. The only way to do this is to multiply both sides by Time/1 to cancel out time on the Displacement/Time side and to make it so Velocity is multiplied by time. So Time/1 x Velocity = Displacement/Time x Time/1. The time and the time on the right side of the equation cancel out to become onem and the new equation is Time x Velocity = Displacement. Try it on paper if it becomes to confusing reading my type. Hope this helps!


Graphical representation of motion?

Position-Time GraphYou can graph motion on a position vs time graph. On a position vs time graph, position is on the y-axis and time is on the x-axis. If the velocity is constant, the graph will be a straight line and the slope is average velocity. If the motion is accelerating, the graph will be a curved line.Velocity-Time GraphYou can also graph motion on a Velocity-Time graph. On a velocity vs time graph, velocity is on the y-axis, time is on the x-axis. If the graph is a straight line, velocity is constant and the slope is average acceleration. Also, on a velocity vs time graph, the area under the line is displacement.Refer to the related link for illustrations of the different graphs of motion and their meanings.


How does connecting the points on a graph affect your data analysis?

They make points in space related to each other. Now they are connected in the problem, instead of just points on the graph.


What points make a vertical line on a graph?

any points along the line described by the equation x=anything will give you a vertical line on a graph