The expression for the radius of the nth dark ring is given as rn2 = n R l
Here l is the wavelength of monochromatic source.
R- the radius of curvature of the plano convex lens
n is the order of the ring.
Theoretically we can get value of R knowing other quantities.
But practically we use the following expression
R = r n+m 2 - r n 2 / m l
This would reduce the error due to non symmetry of the smaller rings.
The curvature of the Earth in any direction can be calculated using the formula for the Earth's radius of curvature (R), which is given by R = a / √(1 - e^2sin²φ) where a is the equatorial radius of the Earth and e is the eccentricity of the Earth. By determining the radius of curvature at a specific latitude (φ), you can find the curvature in that direction.
To find the focal point of a convex mirror, you can use the formula: f = R/2, where R is the radius of curvature of the mirror. The focal point of a convex mirror is located behind the mirror, at a distance equal to half the radius of curvature.
The refractive index of a liquid can be determined using Newton's rings by observing the pattern of concentric bright and dark fringes produced when light reflects off the liquid-air interface. By measuring the diameter of the rings and applying the formula relating ring radius to the refractive index of the liquid and the wavelength of light, the refractive index can be calculated. The relationship is given by: n = (R^2 - r^2) / (2t*r), where n is the refractive index, R is the radius of curvature of the lens, r is the radius of a bright ring, and t is the thickness of the liquid film.
That depends on the situation, on the problem you are trying to solve. If speed is constant, maximal centripetal acceleration occurs where the radius of curvature is smallest - for example, in the case of a parabola, at its vertex. If the radius of curvature is constant, maximum centripetal acceleration occurs when the speed is greatest (for an object reacting to gravity, that might be at the bottom of a circular path). In other cases, you have to get a general expression for the centripetal acceleration, and maximize it (using methods of calculus).
If an object at is 2.5 cm long is placed on the axis of a concave mirror that is 30 cm radius of curvature at a distance of 10 cm away from it, the position size and nature of the image formed would be 20 cm. This is a math problem.
radius of curvature = 2Focal length
There is a specific formula for finding the radius of a curvature, used often when one is measuring a mirror. The formula is: Radius of curvature = R =2*focal length.
The radius of curvature and the focal length mean the same so the radius of curvature is also 15 cm.
The curvature of the Earth in any direction can be calculated using the formula for the Earth's radius of curvature (R), which is given by R = a / √(1 - e^2sin²φ) where a is the equatorial radius of the Earth and e is the eccentricity of the Earth. By determining the radius of curvature at a specific latitude (φ), you can find the curvature in that direction.
There is not enough information to answer the question.
You need to do your differentiation in terms of polar coordinates
To find the focal point of a convex mirror, you can use the formula: f = R/2, where R is the radius of curvature of the mirror. The focal point of a convex mirror is located behind the mirror, at a distance equal to half the radius of curvature.
Given a set of x and y coordinates, fit a curve to it using statistical techniques. The radius of curvature for the set of points is the radius of curvature for this arc. To find that, the curve must be differentiable twice. Let the curve be represented by the equation y = y(x) and let y' and y" be the first and second derivatives of y(x) with respect to x.Then R = abs{(1 + y'^2)^(3/2) / y"} is the radius of curvature.
The refractive index of a liquid can be determined using Newton's rings by observing the pattern of concentric bright and dark fringes produced when light reflects off the liquid-air interface. By measuring the diameter of the rings and applying the formula relating ring radius to the refractive index of the liquid and the wavelength of light, the refractive index can be calculated. The relationship is given by: n = (R^2 - r^2) / (2t*r), where n is the refractive index, R is the radius of curvature of the lens, r is the radius of a bright ring, and t is the thickness of the liquid film.
That depends on the situation, on the problem you are trying to solve. If speed is constant, maximal centripetal acceleration occurs where the radius of curvature is smallest - for example, in the case of a parabola, at its vertex. If the radius of curvature is constant, maximum centripetal acceleration occurs when the speed is greatest (for an object reacting to gravity, that might be at the bottom of a circular path). In other cases, you have to get a general expression for the centripetal acceleration, and maximize it (using methods of calculus).
First, divide 180 by pi (3.14159).Multiply that answer by 100.You should have approximately 5729.5779514.This result we will refer to as the Circular Ratio.Divide the Circular Ratio by the Radius of the curve.The answer is The Degree Of Curvature for that curve.Graphically: measure the angle it takes to make a curve 100 feet long.That angle is The Degree Of Curvature for that curve.
Also if you mean Newtons in terms of weight the formula is Newtons = Mass * Gravity