Want this question answered?
Don't give us the options then!! If one parent had 2 dominant genes then all offspring would have dominant phenotype, the same goes for both parents having dominant genes.
Punnett squares demonstrate the percentage of traits that are passed on from one generation to the next. It shows the pairings of dominant and recessive genes and what percentage there is of the next generation having those particular traits.
Yes, if both parents each have the dominant positive AND recessive negative genes, they have a 1 in 4 chance of having a child with rh-neg blood. Both mother and father would have to pass the recessive gene to the offspring.
9:3:3:1 The probability of having both recessive traits is 1:16.
Genes are passed down from parents to offspring. That's why the mutant gene would be in the offspring.
The offspring has a 50% chance of the dominate trait (while being heteroygous) and a 50% chance of having the recessive trait ( homozygous recessive).
I don't know and don't care
No genes disappear in the F1 generation. Each of the F1 plants was heterozygous, having both a dominant and recessive alleles. The recessive phenotype disappears in the F1 generation because all members of that generation carry a dominant allele. In the F2 generation, the recessive phenotype will reappear.
No genes disappear in the F1 generation. Each of the F1 plants was heterozygous, having both dominant and recessive alleles. The recessive phenotype disappears in the F1 generation because all members of that generation carry a dominant allele. In the F2 generation, the recessive phenotype will reappear.
having offspring. i.e reproduction.
an autosomal recessive disorder, meaning that having an affected offspring requires both unaffected parents to be carriers. Parents who carry the disorder will have a 25% risk of having an affected offspring in subsequent pregnancies.
i dont know all about it but he says that the mother and the father both pass genes to their offspring even though they may not show for example their fathers blue eyes but they show their mothers green eyes. the blue eyes is a recessive gene they will pass to their offspring. so it may skipa generation and come back because the offspring carry that gene. no gene is lost until it has passed 2 generations without a mother or father having it of the offspring have it.
Since the F1 generation of crosses is a cross between two pure traits (for example, TT for tall and tt for short/dwarfness), the offspring of the pure parents all have the genotype of Tt: 100% of offspring will be tall. The dwarfness seems to "disappear" because the capital T is dominant, while the lowercase t (for shortness) is recessive. Dominant dominates a recessive trait, so only tallness appears and dwarfness seems to disappear. Additional Info: However, even though the dwarfness seems to "disappear" it is still in the genotype although it does not appear in the F1 generation. In the F2 generation, there will be a 25% chance of the offspring having the trait dwarfness, because the F1 generation is crossed (Tt x Tt).
Hemochromatosis can skip generations because it is an autosomal recessive genetic disorder. This means that an individual can carry a gene for hemochromatosis without showing symptoms, and it may not be expressed in every generation. The risk of developing the condition depends on inheriting two copies of the mutated gene, one from each parent.
Don't give us the options then!! If one parent had 2 dominant genes then all offspring would have dominant phenotype, the same goes for both parents having dominant genes.
When a parent for example has one dominant and onee recessive e.g Fe and another parent is a carrier for it e.g ee this will make the gene produce a trait of the offspring having a 50% chance of being a carrier
The resulting offspring will have 50% chance of having straight toes and being heterozygous, and 50% chance of having curled toes and being recessive.