The horizontal distance traveled by the ball can increase by increasing the initial velocity of the ball or by reducing the effect of air resistance. Additionally, increasing the launch angle of the ball can also help it travel further horizontally.
Oh, dude, let me break it down for you. So, Norma kicks the ball at 10.0 m/s at 30 degrees. The horizontal distance the ball travels can be calculated using the formula: distance = velocity * time. Just plug in the numbers and solve for the horizontal distance. It's like a piece of cake, man.
The time the ball was in the air can be calculated using the horizontal distance it traveled and its initial horizontal velocity. Time = distance / velocity. In this case, time = 45m / 15 m/s = 3 seconds.
The total distance traveled by the ball when it reaches the ground is 24 meters. The ball travels 8 meters as it falls, and then bounces back half the distance (4 meters) and continues this pattern until it reaches the ground.
Hold up, whoa ! Just wait a second there.If the table-top is 1 meter from the floor, then the ball hits the floor 0.45 seconds after itrolls off the edge of the table. The horizontal speed makes no difference.A cannonball fired horizontally from the cannon and a cannonball dropped from the muzzleof the cannon hit the ground at the same time. Horizontal speed doesn't keep anything upany longer than if it drops straight down with no horizontal speed.If the ball is rolling horizontally along the table at 2 m/s, then it falls to the floor 0.45 secondsafter it reaches the edge, and in that period of time, it sails (2 x 0.45) = 0.9 meter out past theend of the table.
Using the kinematic equation for projectile motion, the horizontal distance the ball traveled is given by the formula: (d = v_{i} \cdot t \cdot \cos(\theta)) where (v_{i}) is the initial speed, (t) is the time of flight, and (\theta) is the angle of projection. Plugging in the given values, we get: (d = 25 \cdot 2.55 \cdot \cos(35) \approx 49.6 , m)
Oh, dude, let me break it down for you. So, Norma kicks the ball at 10.0 m/s at 30 degrees. The horizontal distance the ball travels can be calculated using the formula: distance = velocity * time. Just plug in the numbers and solve for the horizontal distance. It's like a piece of cake, man.
To find the horizontal distance the soccer ball traveled before hitting the ground, we can use the projectile motion equations. The horizontal component of the initial velocity is ( v_x = 26 \cos(30^\circ) ) and the vertical component is ( v_y = 26 \sin(30^\circ) ). The time of flight can be calculated using the vertical motion equation, and then the horizontal distance can be found by multiplying the horizontal velocity by the time of flight. The total distance traveled by the ball is approximately 34.5 meters.
The time the ball was in the air can be calculated using the horizontal distance it traveled and its initial horizontal velocity. Time = distance / velocity. In this case, time = 45m / 15 m/s = 3 seconds.
about 5,00 miles
The total distance traveled by the ball when it reaches the ground is 24 meters. The ball travels 8 meters as it falls, and then bounces back half the distance (4 meters) and continues this pattern until it reaches the ground.
Distance traveled and time taken to travel that distance.
Hold up, whoa ! Just wait a second there.If the table-top is 1 meter from the floor, then the ball hits the floor 0.45 seconds after itrolls off the edge of the table. The horizontal speed makes no difference.A cannonball fired horizontally from the cannon and a cannonball dropped from the muzzleof the cannon hit the ground at the same time. Horizontal speed doesn't keep anything upany longer than if it drops straight down with no horizontal speed.If the ball is rolling horizontally along the table at 2 m/s, then it falls to the floor 0.45 secondsafter it reaches the edge, and in that period of time, it sails (2 x 0.45) = 0.9 meter out past theend of the table.
60
50m
A trajectory is the angle made with the horizontal when a projectile is fired. Suppose the projectile is a cannon ball. Assuming air is frictionless, that cannon ball will travel the greatest distance if the trajectory is 45 degrees from horizontal.
Distance traveled divided by how much time determines speed. Speed=distance/time
Using the kinematic equation for projectile motion, the horizontal distance the ball traveled is given by the formula: (d = v_{i} \cdot t \cdot \cos(\theta)) where (v_{i}) is the initial speed, (t) is the time of flight, and (\theta) is the angle of projection. Plugging in the given values, we get: (d = 25 \cdot 2.55 \cdot \cos(35) \approx 49.6 , m)