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It makes a line ,it goes through the origin, it has a constant
It is the gradient of the straight line joining the origin to any point on the graph. Thus, if A = (p,q) is any point on the graph, the average unit rate between the origin and A is q/p (provided p is non-zero).
no
the slope is 1, and goes through the origin. It's a straight, diagonal line.
it is just that- a linear function that goes through ther origin. ======================================================= Any equation y = ax, where a is a constant, will do so.
No
It makes a line ,it goes through the origin, it has a constant
It is the gradient of the straight line joining the origin to any point on the graph. Thus, if A = (p,q) is any point on the graph, the average unit rate between the origin and A is q/p (provided p is non-zero).
It may or may not exist. Whether or not the graph goes through the origin does not in any way affect whether or not it has a derivative. A function has a derivative if it has no discontinuities, cusps, sharp corners, or vertical tangents.
Divide the ordinate (y-coord) of any point on the graph by its abscissa (x-coord).
no
It's a slanted straight line that goes through the origin of the coordinates.
goes through the origin, up and to the right
the slope is 1, and goes through the origin. It's a straight, diagonal line.
-- Take the equation -- Set either 'x' or 'y' equal to zero -- Solve the resulting equation for the remaining variable -- If the remaining variable is then also zero, then the origin is on the graph of the function If the graph is a straight line ('x' and 'y' appear in the equation only to the 1st power), then the equation has to be in the form of a simple ratio ... like (y = Kx) or (x = Ky) or (xy = K) or (x/y = K) ... in order to go through the origin.
as pressure goes UP, temp. goes DOWN as temp. goes UP, pressures goes DOWN
It is in quadrants 1 and 2 It is v shaped it goes through the origin hope this helps!