When crosses were made taking into account two dominant charater in a parent with
another parent having racessive genes for those characters, in F1 generation all plants had dominant characters but in F2 generation, on self-pollination, the segregation in both the characters were observed independent of each other.
It helps if you know how to set up the problem in a Punnett square and look at the results. For now, let's just say that for a dihybrid cross is between a plant with green, wrinkled seeds and one with yellow round seeds. The traits of green (G) is dominant over yellow(g) and round (R) is dominant over wrinkled (r). If the traits were "connected" then the offspring should be one or the other of the parental types. But in reality, you'll get plants with green, smooth seeds as well, since a plant with one "R" allele is all that's necessary to produce a plant with the dominant round seeds.
And if the cross was between two heterozygous plants (GgRr x GgRr all with the phenotype of green round seeds), the offspring will be a mix of plants with a ratio of 9 green and round to 3 green and wrinkled, to 3 yellow and smooth, to 1 yellow and wrinkled. So if 1600 offspring were produced, there would be approximately 900 with both characteristics showing the dominant phenotype, 300 wit just one trait being dominant, 300 with the opposite trait being dominant, and 100 with neither dominant characteristic instead of all being the dominant characteristics like the parents. Or 50/50. So this shows that the chromosomes that carry these characteristics are independent of each other.
chide
to find out if traits could effect the inheritance of other traits
when two or more characteristics are inherited, individual hereditary factors assort independently during gamete production, giving different traits an equal opportunity of occurring together.
Yes, it is true. Mendels principles apply to anything and everythin that is living.
The probabilty can be applied to meiosis.
due to linkage..
turd
When crosses were made taking into account two dominant charater in a parent with another parent having racessive genes for those characters, in F1 generation all plants had dominant characters but in F2 generation, on self-pollination, the segregation in both the characters were observed independent of each other.
law of segregation, independent assortment, and dominance.
to find out if traits could effect the inheritance of other traits
In crossing over and random assortment.
Examples of Law of Independent AssortmentThe law of independent assortment applies well to most plants and animals, but only to those genes which occur on non-homologous autosomal chromosomes. Here, following dihybrid crosses of guinea pigs and Drosophila can be considered as the examples for law of independent assortment in animals.1. When a black short haired guinea pig (BB SS, the black colour and short hairs dominate over brown colour and longhairs respectively) and a brown, long-haired- guinea pig (bb ss) are mated, the BB SS individuals produce gametes all of which are BS. The bb ss guinea pigs produce only bs gametes. Each gamete contains one and only one of each kind of gene. The union of BS gametes and bs gametes yields F1 heterozygous, black, short haired individuals with the genotype of Bb Ss.However, when two of the F1 individuals are mated each produces four kinds of gametes in equal numbers-BS, Bs, bS, bs. These gametes unite to produce 16 combinations in F1 in the phenotypic ratio of 9 black, short haired: 3 black, long haired: 3 brown, short haired: 1 brown, long haired or 9 : 3 : 3 : I. The results of this cross have been represented by following diagram.F2 Eggs Sperms 3-Black, Short Black, Short Black, Short Black, Short Black, Short Black, Short 3-Black, Long Black, Long Black, Long Black, Long Black, Long Black, Long 3-Brown, Short Brown, Short Brown, Short Brown, Short Brown, Short Brown, Short 1-Brown, Long Brown, Long Brown, Long Brown, Long Brown, Long Brown, LongThe results of this cross clearly show that the segregation of the B-b genes is independent of the segregation of the S-s genes.http://www.microbiologyprocedure.com/genetics/dihybrid-crosses-and-mendels-law-of-independent-assortment/examples-of-law-of-independent-assortment-in-animals.htm
when two or more characteristics are inherited, individual hereditary factors assort independently during gamete production, giving different traits an equal opportunity of occurring together.
Yes, Gregor Mendel experimented with pea plants, specifically their pea pods, in his groundbreaking studies on inheritance and genetics. By studying the patterns of inheritance in pea plants, Mendel was able to establish the fundamental principles of genetics.
the law of independent assorment
Doron Mendels was born in 1944.
Law of Independent Assortment (The "Second Law")The Law of Independent Assortment, also known as "Inheritance Law", states that separate genes for separate traits are passed independently of one another from parents to offspring. That is, the biological selection of a particular gene in the gene pair for one trait to be passed to the offspring has nothing to do with the selection of the gene for any other trait. More precisely, the law states that alleles of different genes assort independently of one another during gamete formation
It helps if you know how to set up the problem in a Punnett square and look at the results. For now, let's just say that for a dihybrid cross is between a plant with green, wrinkled seeds and one with yellow round seeds. The traits of green (G) is dominant over yellow(g) and round (R) is dominant over wrinkled (r). If the traits were "connected" then the offspring should be one or the other of the parental types. But in reality, you'll get plants with green, smooth seeds as well, since a plant with one "R" allele is all that's necessary to produce a plant with the dominant round seeds. And if the cross was between two heterozygous plants (GgRr x GgRr all with the phenotype of green round seeds), the offspring will be a mix of plants with a ratio of 9 green and round to 3 green and wrinkled, to 3 yellow and smooth, to 1 yellow and wrinkled. So if 1600 offspring were produced, there would be approximately 900 with both characteristics showing the dominant phenotype, 300 wit just one trait being dominant, 300 with the opposite trait being dominant, and 100 with neither dominant characteristic instead of all being the dominant characteristics like the parents. Or 50/50. So this shows that the chromosomes that carry these characteristics are independent of each other.