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89,999 different numbers i guess
IF we use four different digits ,For example 12 , 35. 98. 72 . when we add two 2 -digits numbers. 12 + 35 =47 98 + 72 =160 72 + 35 = 107 98 + 12 = 110 the least sum we can get 12+ 35 = 47.
There are only five distinct odd digits.
Different schemes have different id numbers of different lengths.
12689 14689 12489
What is the largest number you can make from the digits 8,6,9,1 explain how you make the number
89,999 different numbers i guess
There are 7,290 different 4-digit numbers that can be formed from the digits 1-9 without repetition.
IF we use four different digits ,For example 12 , 35. 98. 72 . when we add two 2 -digits numbers. 12 + 35 =47 98 + 72 =160 72 + 35 = 107 98 + 12 = 110 the least sum we can get 12+ 35 = 47.
There are only five distinct odd digits.
Different schemes have different id numbers of different lengths.
Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.
12689 14689 12489
If the digits are all different then 18. Otherwise, 192.
The answer will depend on how many digits you have at your disposal. Working with the 10 digits, and barring leading zeros, there are 8,877,690 numbers.
12 numbers.
You have seven different digits (symbols) to choose from, so you can form seven different one digit numbers and 7×7=72=49 different two digit numbers.