The chemical equation is:
4 Fe + 3 O2 + 2 H2O = 4 FeO(OH)
It depends whether you are using Iron (III) or Iron (II)
2h2 + o2 = 2h2o
H2 and O2.
Balanced equation first. 2H2 + O2 >> 2H2O 1.42 mol H2 ( 1mol O2/2mol H2 ) = 0.71mol O2 to react with H2
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
2Na + 2H2O -------> 2NaOH + H2
One possible product of each is gvien below: 1. Ca + SO3 = CaSO3 2. SbCl3 + Cl2 = SbCl5 3. N2 + 3 H2 = 2 NH3 4. S + O2 = SO2
2SO2 + O2 + 2H2O -------> 2H2SO4
This simple equation is: 2H2 + O2 = 2H2O
= H2+O2 =2H2+O2=2H2O
H2 and O2.
Zn+ H2O ---> ZnO + H2 Zn+ H2O ---> ZnO + H2
2h2 + o2 -> 2h2o stupid wiki is not allowing capitalization again!! Know that all the letters are capitals.
No. It would have to be H2O2 - H2 = O2 in order to be balanced.
Hydrogen peroxide.
Balanced equation first. 2H2 + O2 >> 2H2O 1.42 mol H2 ( 1mol O2/2mol H2 ) = 0.71mol O2 to react with H2
First off, you decide the product (becomes easier after a while of doing chemistry). The product is H2O (water). O2+H2=>H2O, but this is not stochiometrically balanced, so you have to change the amount of H2O's on the right side of equation and then to balance the amount of hydrogens. If you add a 2 in front of both, you get O2 + 2H2 => 2H2O
hydrogen peroxide
2Na + 2H2O -> H2 + 2NaOH