K3PO4 + 3HCl -> 3KCl + H3PO4
Since K on the reactant side has 3 potassium atoms, K on the product side should also have 3 potassium atoms to balance the equation. Since you put the 3 on KCl of the product side, another 3 has to go on the Cl on the reactant side which also matches the 3 hydrogen atoms on the product side in H3PO4. If you check, the equation is now balanced. Everything that appears on the left, equally appears on the right
3KOH (aq) + H3PO4 (aq) --> 3H2O (l) + K3PO4(aq)
NaOH plus H3PO4 > Na2HPO4 plus H2O
Look at the products. You should already know that one is bound to be water, H2O. You know that the OH comes from KOH, and the H comes from H3PO4. So ask yourself the question: How many OH and how many H are available? You can see that since you have three of one, you will also need three of the other, so you need 3 of the KOH, right? So this is the equation: 3KOH + H3PO4 -> 3H2O + K3PO4
The chemical equation is:H3PO4 + 3 KOH = K3PO4 + 3 H2O
KOH for potassium hydroxide, and H3PO4 for phosphoric acid.
When solving this type of problem, first use the ion charges to predict the formulas of the products. Then use coefficients to balance the equation. H3PO4 (aq) + 3 KOH (aq) --> K3PO4 (aq) + 3 H2O (l)
HI
Look at the products. You should already know that one is bound to be water, H2O. You know that the OH comes from KOH, and the H comes from H3PO4. So ask yourself the question: How many OH and how many H are available? You can see that since you have three of one, you will also need three of the other, so you need 3 of the KOH, right? So this is the equation: 3KOH + H3PO4 -> 3H2O + K3PO4
The chemical equation is:H3PO4 + 3 KOH = K3PO4 + 3 H2O
my balance sheet does not balance why?
KOH for potassium hydroxide, and H3PO4 for phosphoric acid.
Balanced equation:12 HClO4 + P4O10 = 4 H3PO4 + 6 Cl2O7
When solving this type of problem, first use the ion charges to predict the formulas of the products. Then use coefficients to balance the equation. H3PO4 (aq) + 3 KOH (aq) --> K3PO4 (aq) + 3 H2O (l)
Na3PO4+H2O->NaOH+H3PO4 just balance it.
HI
first find out what the 'relative atomic mass' all the elements in the equation have. for example: __ KOH +____________________ H3PO4 → ______ K3PO4 + __ H2O k=39 O=16<-add them together(56)+H3(1x3) p=31 and O4=16x4 (and so on....) H= 1 anyway, continue doing that until you find out all the relative atomic masses, add each section together- so add what you get for KOH and H3PO4 but make sure that you don't add it on to K3PO4 and H2O because they're separate sections. after finsing out the score for each side, see which side has the highest number and
Example:NH4OH + KNO3 -----------NH4NO3 + KOH
k+h2o>koh+h2
Phosphoric acid. H3PO4