K3PO4 + 3HCl -> 3KCl + H3PO4
Since K on the reactant side has 3 potassium atoms, K on the product side should also have 3 potassium atoms to balance the equation. Since you put the 3 on KCl of the product side, another 3 has to go on the Cl on the reactant side which also matches the 3 hydrogen atoms on the product side in H3PO4. If you check, the equation is now balanced. Everything that appears on the left, equally appears on the right
KOH for potassium hydroxide, and H3PO4 for phosphoric acid.
The coefficient in front of water in the balanced chemical equation for the reaction between H3PO4 and KOH to form K3PO4 and water is 4. This means that four molecules of water are formed in this reaction for every one molecule of H3PO4 and three molecules of KOH that react.
When solving this type of problem, first use the ion charges to predict the formulas of the products. Then use coefficients to balance the equation. H3PO4 (aq) + 3 KOH (aq) --> K3PO4 (aq) + 3 H2O (l)
H3PO4 is Phosphoric Acid. What are you reacting it with, in order to balance the eq'n.
Look at the products. You should already know that one is bound to be water, H2O. You know that the OH comes from KOH, and the H comes from H3PO4. So ask yourself the question: How many OH and how many H are available? You can see that since you have three of one, you will also need three of the other, so you need 3 of the KOH, right? So this is the equation: 3KOH + H3PO4 -> 3H2O + K3PO4
KOH for potassium hydroxide, and H3PO4 for phosphoric acid.
The coefficient in front of water in the balanced chemical equation for the reaction between H3PO4 and KOH to form K3PO4 and water is 4. This means that four molecules of water are formed in this reaction for every one molecule of H3PO4 and three molecules of KOH that react.
When solving this type of problem, first use the ion charges to predict the formulas of the products. Then use coefficients to balance the equation. H3PO4 (aq) + 3 KOH (aq) --> K3PO4 (aq) + 3 H2O (l)
H3PO4 is Phosphoric Acid. What are you reacting it with, in order to balance the eq'n.
Look at the products. You should already know that one is bound to be water, H2O. You know that the OH comes from KOH, and the H comes from H3PO4. So ask yourself the question: How many OH and how many H are available? You can see that since you have three of one, you will also need three of the other, so you need 3 of the KOH, right? So this is the equation: 3KOH + H3PO4 -> 3H2O + K3PO4
my balance sheet does not balance why?
To balance the reaction between H3PO4 and NaOH, first write out the chemical equation: H3PO4 + 3 NaOH -> Na3PO4 + 3 H2O Now, each element must have the same number of atoms on both sides of the equation for it to be balanced. Adjust the coefficients in front of each compound to achieve this balance.
Balanced equation:12 HClO4 + P4O10 = 4 H3PO4 + 6 Cl2O7
The salt formed from the neutralization of phosphoric acid (H3PO4) with potassium hydroxide (KOH) is potassium phosphate (K3PO4).
Na3PO4+H2O->NaOH+H3PO4 just balance it.
first find out what the 'relative atomic mass' all the elements in the equation have. for example: __ KOH +____________________ H3PO4 → ______ K3PO4 + __ H2O k=39 O=16<-add them together(56)+H3(1x3) p=31 and O4=16x4 (and so on....) H= 1 anyway, continue doing that until you find out all the relative atomic masses, add each section together- so add what you get for KOH and H3PO4 but make sure that you don't add it on to K3PO4 and H2O because they're separate sections. after finsing out the score for each side, see which side has the highest number and
The chemical formula for phosphoric acid is H3PO4.