To balance any chemical equation, first ensure that you have the correct formulae for all the reactants and products:
BaCl2 + H2SO4 ------> BaSO4 + HCl
Then work methodically through the equation, making sure that there are the same numbers of each element present on either side of the equation.
In this case, we need an extra chlorine on the right hand side, and an extra hydrogen on the RHS, so the result?
BaCl2 + H2SO4 -------> BaSO4 + 2HCl
BaCl2 + H2SO4 → BaSO4 + 2HCl Reactants Products
When barium chloride (BaCl2) reacts with sulfuric acid (H2SO4) in a double displacement reaction, barium sulfate (BaSO4) and hydrochloric acid (HCl) are formed. The balanced chemical equation for this reaction is BaCl2 + H2SO4 -> BaSO4 + 2HCl.
Ba+2(aq)+So4_2(aq)===> BaSo4(s)
The balanced equation for sulfuric acid (H2SO4) reacting with barium carbonate (BaCO3) is: H2SO4 + BaCO3 -> BaSO4 + H2O + CO2
Ba(OH)2(aq) + H2SO4(aq) ---> BaSO4(s) + 2H2O(l)
BaCl2 + H2SO4 → BaSO4 + 2HCl Reactants Products
When barium chloride (BaCl2) reacts with sulfuric acid (H2SO4) in a double displacement reaction, barium sulfate (BaSO4) and hydrochloric acid (HCl) are formed. The balanced chemical equation for this reaction is BaCl2 + H2SO4 -> BaSO4 + 2HCl.
Ba+2(aq)+So4_2(aq)===> BaSo4(s)
The balanced equation for sulfuric acid (H2SO4) reacting with barium carbonate (BaCO3) is: H2SO4 + BaCO3 -> BaSO4 + H2O + CO2
Ba(OH)2(aq) + H2SO4(aq) ---> BaSO4(s) + 2H2O(l)
The chemical equation is MgSO4 + CaCl2 --> MgCl2 + CaSO4
This equation is Ba(OH)2 + H2SO4 -> BaSO4 + H2O.
The balanced equation for the reaction between Ba(OH)2 and H2SO4 is: Ba(OH)2 + H2SO4 → BaSO4 + 2 H2O. This reaction forms BaSO4 (barium sulfate) and water.
Ba + H2SO4 ---> BaSO4 + H2
The balanced chemical equation for the reaction between barium bromide (BaBr2) and sodium sulfate (Na2SO4) is: BaBr2(aq) + Na2SO4(aq) → BaSO4(s) + 2NaBr(aq) In this reaction, barium sulfate (BaSO4) and sodium bromide (NaBr) are formed. The equation is balanced as the number of atoms of each element is the same on both sides of the equation.
Molecular:Bacl2(aq)+K2SO4(aq)-->BaSO4(s)+2KCl(aq)Total Ionic:Ba+2(aq) + 2Cl-(aq) + 2K+(aq) + SO4-2(aq)-->BaSO4(s) + 2K+(aq) + 2Cl-(aq)Net Ionic:Ba+2(aq) + SO4-2(aq)-->BaSO4(s)The ionic equation would have the ionic charges of each compound/element/or whatever. Ba^+2 CL^- for the first.. etc. You do the 'criss-cross' method to determine the ionic charges, and write that into the equation.This is a double-replacement precipitation type of reaction.
Ba(OH)2 + H2SO4 react to form BaSO4 + 2H2O