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absolute pressure of liquid = atmospheric pressure (P₀) + (relative density (ρ) of liquid x height of liquid x gravitational acceleration)

P₀ = 103000 Pa

ρ of sea water at 15°C = 1025 kg/m³

h = 55 m

g = 9.81m/s²

Answer = 103000 Pa + (1025 kg/m³ x 9.81 m/s² x 55 m)

Answer = 6.56 x 10^5 Pa

(Sorry about using the carat in signifying the scientific notation, but apparently I cannot find a way to type a superscript 5 using code.)

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โˆ™ 2010-03-23 15:24:46
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Q: How do you calculate absolute pressure at 55 metres below sea level when atmospheric pressure is 103 kilo pascals?
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