If you mean light of a given wavelength, then the energy E per photon is given by the formula:
E = hc/λ,
where h is Planck's constant, c is the speed of light and λ is the wavelength.
You don't need to 'calculate' the frequency of your power supply, as it's openly publicised. However, if you want to do so as an academic exercise, then you could do so as follows (but you'd need very accurate instruments, and you'd need to take very careful measurements!):
Well, that's how you could do it, theoretically. Not quite as easy in practise, though, as accuracy would be essential! I recommend that you ask your supply company!!!
You can just use frequency to calculate energy
E=hf
where E=energy
h=planck's constant=6.626×
10−34
J/s
f= frequency
?
But if you are given the wavelength, you might need this:
since v= λ
x f
where v=speed
? λ=wavelength? f=frequency
and v=c= speed of light=
3x108m/s
Hence, E= hf= h(c÷
λ)
The relation is the following:
e = h.f, where:
- e is the energy in joules
- h is the Planck constant: 6,626 069 572 9.10-34 joule.second
- f is the frequency in cycles/second
And consequently the energy is 2,2065.10-19 joules
The relation is the following:
e = h.f, where:
- e is the energy in joules
- h is the Planck constant: 6,626 069 572 9.10-34 joule.second
- f is the frequency in cycles/second
E=hf, where h is Plank's Constant (look it up for the value)
Given wavelength w, the power is h(c/w)^2 = hc^2/w^2 = 6E-17/w^2
Photon energy = (frequency) times (Planck's Konstant)
4.59 x 10^-19
what is the energy of a photon that has a frequency of 5.0x1014 Hz?
use the equation E = hf where h is plancks constant E = 410E 7 * 6.63E -34 E = 2.7183E -23 joules
A frequency converter converts an alternating current from one frequency to another. This is typically measured in Hertz (Hz).
The higher the frequency of a wave, the higher its energy
5.3x10^-21
No, the joule (J) is a unit of energy. Frequency is measured in cycles per second, which is also called hertz(Hz).
The energy is 2,9619.e-19 J.
The energy of a photon is given by the equation: E = h * f where E is the energy of the photon, h is Planck's constant, and f is the frequency of the photon. Plugging in the given frequency of 5 × 10^20 Hz, and using the value of Planck's constant h = 6.626 x 10^-34 joule seconds, we get: E = (6.626 x 10^-34 J s) * (5 x 10^20 Hz) = 3.313 x 10^-13 joules Therefore, the energy of a photon with a frequency of 5 × 10^20 Hz is approximately 3.313 x 10^-13 joules.
The energy of a photon when frequency is known is E = hv, where E is energy in Joules, h is Planck's constant, 6.626 x 10-34 Joule•second, and v is frequency.E = 6.626 x 10-34 J•s x 4.47 x 1014 Hz = 2.96 x 10-19 Joules
The energy is E=hf= 2/3E-33 x 5E14= 1/3 E-18 Joules.
1 GHz = 1*109 Hz. To convert GHz to Hz multiply by 1*109 To convert Hz to GHz divide by 1*109
Hz is short for hertz. It is not a time, but a frequency. Time is measured in seconds, Hz is equivalent to 1/seconds. Therefore, you can't convert between time and frequency.
what is the energy of a photon that has a frequency of 5.0x1014 Hz?
You don't. Hz (always capitalized) is the unit for measuring frequency or pitch. dB is the unit for measuring amplitude or relative loudness of the sound. You cannot convert a frequency measurement to an amplitude measurement.
You cant. Hz measures frequency, where as Watts is a measurement of power.
to find the frequency of a light wave you need to know its wavelength. The frequency is equal to the speed of light (3x10^8 m/s) divided by the wavelength in metres. Alternatively, if you were given the energy of each photon of light in joules you could just divide the energy by plancks constant (6.63x10^-34) to leave you with the frequency in Hz.
use the equation E = hf where h is plancks constant E = 410E 7 * 6.63E -34 E = 2.7183E -23 joules