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some basic physics will tell you that the mass of the box times acceleration due to gravity times the height of the box above the ground, minus the force of the spring or the spring constant times the distance the spring stretches will equal .5 times the mass of the box times the velocity squared mgh-kx=.5mv2
Let a mass m be attached to the end of a spring with spring constant k. The spring extends and comes to rest with an equilibrium extension e. At equilibrium; Weight = Force exerted by spring => mg = ke -------- 1 Suppose the spring is displaced through a displacement x downwards from its equilibrium position: Resolving vertically, we have; Resultant force on mass = Force exerted by spring - Weight of mass => ma = k(e + x) - mg ------- 2 From 1, we have: ma = mg + kx - mg => a = (k/m)x Since a is proportional to displacement from equilibrium position, the oscillation is simple harmonic. So, (angular velocity)2 = (k/m) => 2pi/T = (k/m)1/2 => T = 2pi (m/k)1/2 This equation shows that the time period is proportional to the square root of the mass of the attached object.
A spring stretches because the coiled spring stores potential energy. This energy is released as the spring is stretched and returns to its original shape. Over a period of time, the spring becomes worn and loses the potential energy.
Get a screen door spring. and then hang a mass on it. Carefully lift it and then let it drop, that gives it up and down motion. Stop the mass, twist it, and then let it go - torsional mode. Stop it and pull it to one side. Now you have a paraconic pendulum. If it's stopped, and you hold the spring where the mass is attached to the spring, turning the mass level (90 degrees from spring axis) counteracts gravity, and the mass will rotate about its center of gravity. Perhaps the spring alone can oscillate. Hold the mass where the spring is attached, and pluck it in the middle If you're not careful in your release, any or all of these can happen at the same time. Since any and all can happen at the same time, then if I counted right, that's 720 modes already.
The elastic potential energy (EEp) of the spring with displacement x from its original length is given by: EEp = 1/2 kx2 (can be proved using integration) where k is the spring constant of the spring. So, if the displacement of the mass is doubled, the elastic EEp stored will increase by 22, that is by 4.
more mass the longer the spring
the ground
some basic physics will tell you that the mass of the box times acceleration due to gravity times the height of the box above the ground, minus the force of the spring or the spring constant times the distance the spring stretches will equal .5 times the mass of the box times the velocity squared mgh-kx=.5mv2
24.5 newtons per meter
Let a mass m be attached to the end of a spring with spring constant k. The spring extends and comes to rest with an equilibrium extension e. At equilibrium; Weight = Force exerted by spring => mg = ke -------- 1 Suppose the spring is displaced through a displacement x downwards from its equilibrium position: Resolving vertically, we have; Resultant force on mass = Force exerted by spring - Weight of mass => ma = k(e + x) - mg ------- 2 From 1, we have: ma = mg + kx - mg => a = (k/m)x Since a is proportional to displacement from equilibrium position, the oscillation is simple harmonic. So, (angular velocity)2 = (k/m) => 2pi/T = (k/m)1/2 => T = 2pi (m/k)1/2 This equation shows that the time period is proportional to the square root of the mass of the attached object.
The gravity survey is carried out with the use of a gravimeter, which uses a fixed length spring and mass attached to a calibration spring.
A spring device can only measure an object's weight. In order to find its mass, you then have to either compare its weight with the weight of a known mass, or else use the value of gravitational acceleration to calculate the mass from the weight.
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A spring stretches because the coiled spring stores potential energy. This energy is released as the spring is stretched and returns to its original shape. Over a period of time, the spring becomes worn and loses the potential energy.
Get a screen door spring. and then hang a mass on it. Carefully lift it and then let it drop, that gives it up and down motion. Stop the mass, twist it, and then let it go - torsional mode. Stop it and pull it to one side. Now you have a paraconic pendulum. If it's stopped, and you hold the spring where the mass is attached to the spring, turning the mass level (90 degrees from spring axis) counteracts gravity, and the mass will rotate about its center of gravity. Perhaps the spring alone can oscillate. Hold the mass where the spring is attached, and pluck it in the middle If you're not careful in your release, any or all of these can happen at the same time. Since any and all can happen at the same time, then if I counted right, that's 720 modes already.
The elastic potential energy (EEp) of the spring with displacement x from its original length is given by: EEp = 1/2 kx2 (can be proved using integration) where k is the spring constant of the spring. So, if the displacement of the mass is doubled, the elastic EEp stored will increase by 22, that is by 4.
Mass balances compare the force of gravity on two masses, while weighing scales use a spring and measure the force of gravity by studying the extension of the spring. A mass balance would give the same answer on the Moon, while the weighing scales would give an answer about a sixth of the correct value.