Remember the equation for acceleration.
a = (v - u ) / t
Were
a = acce;leration
v = final speed ( 20 m/s)
u = initial speed ( 0 m/s)
t = time ( 5 s)
Substituting
a = ( 20 m/s - 0 m/s) / 5s
a = 20m/s / 5s
a = 4 m /s^2
We know acceleration is the rate of change of velocity. now the velocity increases from zero to 20 m/s in an interval of 5 secs. therefore the acceleration is 4 m/s2.
There is a huge difference between constant speed and constant acceleration. Constant speed is when the object is travelling constant, no change in its velocity and acceleration or in other words no extra force to speed up. Constant acceleration when the object is acceleration constant, it means that the speed of the object is change at the same rate each second. The acceleration rate at which the object is travelling is constant. for example, when a car is stationary at a traffic light and it starts acceleration, picking up speed but the rate of acceleration will not constant because the amount of force applied differs each second due to the acceleration rate.
Answer: v=u + at v (Velocity) = u (Starting velocity) + a (acceleration) x t (time) So, starting from stationary (u=0), the velocity is simply a x t e.g. if the acceleration is 5mph per second per second, after 10 seconds you would be travelling at 50mph. Answer: The above is for constant acceleration. In the case of variable acceleration, integration has to be used.
There is not enough information to answer the question. The answer depends onis the object travelling at constant velocity?is the acceleration constant?If it is an object travelling with constant acceleration, which three of the following four variables are knows: initaial velocity, final velocity, acceleration and time.
There is no acceleration if the car is travelling at a steady 54,000 miles per hour.
The speed or velocity of a train has no bearing on its acceleration.
It's called stop cheating on your math papers.
There is a huge difference between constant speed and constant acceleration. Constant speed is when the object is travelling constant, no change in its velocity and acceleration or in other words no extra force to speed up. Constant acceleration when the object is acceleration constant, it means that the speed of the object is change at the same rate each second. The acceleration rate at which the object is travelling is constant. for example, when a car is stationary at a traffic light and it starts acceleration, picking up speed but the rate of acceleration will not constant because the amount of force applied differs each second due to the acceleration rate.
Answer: v=u + at v (Velocity) = u (Starting velocity) + a (acceleration) x t (time) So, starting from stationary (u=0), the velocity is simply a x t e.g. if the acceleration is 5mph per second per second, after 10 seconds you would be travelling at 50mph. Answer: The above is for constant acceleration. In the case of variable acceleration, integration has to be used.
^velocity* Consider an object that is travelling south at 10m/s. It accelerates north until it is travelling 10m/s. If we define south as negative, then it accelerates from -10m/s to 10m/s. -10 < 0 < 10, hence, it is travelling at 0m/s at some point.
There is not enough information to answer the question. The answer depends onis the object travelling at constant velocity?is the acceleration constant?If it is an object travelling with constant acceleration, which three of the following four variables are knows: initaial velocity, final velocity, acceleration and time.
There is no acceleration if the car is travelling at a steady 54,000 miles per hour.
because you are travelling at the same speed, there is no acceleration
Brakes are applied while the car is travelling north. Acceleration is toward the south, car slows down.
The speed or velocity of a train has no bearing on its acceleration.
If it is braking while travelling eastward it is accelerating westward
Jack is driving a car. As he passes post 1 he is travelling at 15ms-1 and starts to accelerate at a steady speed. 8 seconds later he passes post 2 travelling at 30ms-1. Post 1 and 2 are What is his acceleration during this time?
No, it is not possible. For a stationary wave, two identical waves should travel in opposite direction along a string.