You have to use configuration of electrons (spdf). In this case it will only go up to d. if we use the short hand configuration then bromine is 3d10 4s2 4p5. remember d goes before everything.
in the valence shell of bromide 7 electrons are present. So the valency of bromide is 1
Bromine forms anion. It gets a charge of -1 to form bromide ion.
KBr2 does NOT exist, bromide (being Br-) has a valency of (minus) one, so the only possibility is KBr, potassium bromide, in solution as ions: K+ and Br-
The anion (SO4)2- is divalent; the cation Na+ is monovalent.
valency of lithium - 1
-1 valency
The valency of bromide ion (Br-) is -1.
in the valence shell of bromide 7 electrons are present. So the valency of bromide is 1
Bromine forms anion. It gets a charge of -1 to form bromide ion.
The melting point of sodium bromide (a salt) is 755 . Calculate this temperature in and in kelvins.
KBr2 does NOT exist, bromide (being Br-) has a valency of (minus) one, so the only possibility is KBr, potassium bromide, in solution as ions: K+ and Br-
Valency is calculated in this way... 1. Find atm no of that element. 2. Write down electronic configuration. 3. Take the valence shell electron number. 4. The number of electrons to be lost are added as the valency.
The anion (SO4)2- is divalent; the cation Na+ is monovalent.
valency of lithium - 1
valency of Rf =4 valency of Db=5 valency of Sg=6 valency of Bh=7 valency of Hs=8 valency of Mt=unknown
The valency of sulfur is 2-. The valency of sulfur is 2-. The valency of sulfur (S) is +2
The valency of sodium is +1