The molecular equation for the reaction between hydrochloric acid (HCl) and calcium carbonate (CaCO3) is: HCl + CaCO3 → CaCl2 + CO2 + H2O. This reaction produces calcium chloride (CaCl2), carbon dioxide (CO2), and water (H2O) as products.
You can find a answer fromCalcium carbonate - Wikipedia
The reaction between chalk (calcium carbonate, CaCO3) and hydrochloric acid (HCl) can be represented by the chemical equation: CaCO3 + 2HCl → CaCl2 + CO2 + H2O
Hydrochloric acid dissolves in water but does not react with it; there is no equation.
The chemical equation for the reaction between calcium carbonate (CaCO3) and hydrochloric acid (HCl) is: CaCO3 + 2HCl → CaCl2 + CO2 + H2O.
When calcium carbonate (CaCO3) reacts with hydrochloric acid (HCl) the reaction is:- CaCO3 + 2 HCl -> CaCl2 + H2O + CO2 The weight for 1 mole of calcium carbonate is the atomic weight in grams or 40.8 + 12.011 + 3 x 15.9994 = 100.8092 grams 1.25 grams of CaCO3 is therefore 1.25/100.8092 or .0124 mole There must have been twice this many moles of HCl in the solution or 0.0248 mole. The molarity of the solution is the number of moles per litre so with 0.0248 in 25.5 ml there must be .97 mole in 1 litre. The HCl solution must therefore be .97 molar
They are molecules.
The balanced equation for the reaction between hydrochloric acid (HCl) and calcium carbonate (CaCO3) is: 2HCl + CaCO3 -> CaCl2 + H2O + CO2.
You can find a answer fromCalcium carbonate - Wikipedia
CaCO3 + HCl --> CaHCO3 or with excess of HCl CaCO3 + 2HCl --> CaCl2 +CO2 + H2O
The reaction between chalk (calcium carbonate, CaCO3) and hydrochloric acid (HCl) can be represented by the chemical equation: CaCO3 + 2HCl → CaCl2 + CO2 + H2O
Hydrochloric acid dissolves in water but does not react with it; there is no equation.
The chemical equation for the reaction between calcium carbonate (CaCO3) and hydrochloric acid (HCl) is: CaCO3 + 2HCl → CaCl2 + CO2 + H2O.
When calcium carbonate (CaCO3) reacts with hydrochloric acid (HCl) the reaction is:- CaCO3 + 2 HCl -> CaCl2 + H2O + CO2 The weight for 1 mole of calcium carbonate is the atomic weight in grams or 40.8 + 12.011 + 3 x 15.9994 = 100.8092 grams 1.25 grams of CaCO3 is therefore 1.25/100.8092 or .0124 mole There must have been twice this many moles of HCl in the solution or 0.0248 mole. The molarity of the solution is the number of moles per litre so with 0.0248 in 25.5 ml there must be .97 mole in 1 litre. The HCl solution must therefore be .97 molar
The balanced equation for hydrochloric acid (HCl) reacting with calcium carbonate (CaCO3) is: 2HCl + CaCO3 -> CaCl2 + CO2 + H2O.
First write the balanced chemical equation for this reaction CaCO3+2HCl-->CaCl2+H2O+CO2 It is clear from this equation that one mol of HCl can react with half a mol of CaCO3. Thus, one half of .025 mols CaCO3 will react with .025 mols HCl. That makes .0125 mols CaCO3.
The coefficient of HCl in the balanced equation is 2. This is because the balanced equation shows that 1 molecule of CaCl2 reacts with 1 molecule of H2CO3 to form 1 molecule of CaCO3 and 2 molecules of HCl.
The balanced chemical equation for the reaction of calcium carbonate (CaCO3) with hydrochloric acid (HCl) is: CaCO3 + 2HCl → CaCl2 + CO2 + H2O.