0 dBrnc=-90dBm (1000Hz Toned)
How do I convert a .db file?
You cannot convert DBi to DB because they are not related. DBi is only for decibels in an isotropic radiator, while DB is only for decibels in a dipole antenna.
If I understand the question, it isn't possible to convert dB (a unit of sound energy) to litres (a unit of volume).
wb = db/(db+100)
It is impossible to convert dB to dBA. There is only a guess. Scroll down to related links and read "Correlation between sones und phons".
using bode-m plots , one can tranfer dB magnitude to gain and gain to frequency
the first convert the power in dBm to MW, the define of dBm=10 log (P MW) -10 log ( 1mw). example: let P=-2 dBm convert this to dB? answer: Pmw= inv log(-2/10)=0.630mw*1000 micw/mw=630 microw 10log(630)=28dB
Here you find the formula to convert voltage levels to decibels. Scroll down to related links and look at "How to calculate dB?"
dB SPL is a comparison of a sound level to what was thought to be the threshold of hearing, although today it is known that the value was too high. dB HL is a measure of hearing loss - a comparison of a subjects hearing compared to a 'normal' standard. As they are measure different things a direct comparison is not possible. The differences between dB HL and dB SPL, arise from isophonic curves. There is no direct (linear) formula to convert this but a set of formulas. For different frequencies, different values should be added. For eg., at 1kHz you can state that 0dB HL is around 2dB SPL while at 250Hz, 0dB HL is 12 dB SPL. db HL = db Hearing Level db SPL = db Sound Pressure Level
You don't. They measure quite different things, so there is no standard conversion. Ampere is a unit of electrical current. Decibel (dB) is a measure of signal gain.
Decibels (db) is relative power, log base 2, times 3. Increasing power from 200 watts to 400 watts is doubling power, so the decibel change is +3 db.800 watts would be +6 db, 1600 watts would be +9 db, 100 watts would be -3 db, 50 watts would be -6 db, and so on.
In power wattage increases by two times for every three DBs of increase. A starting point is needed to do this calculation. The equation you're looking for is 10*log |P| = P in dB for example, 0 dB = 1 watt 10 dB = 10 watts for 13.936dB, 10^1.3936 = 24.75 watts.