one = een
two = twee
three = drie
four = vier
five = vyf
six = ses
seven = sewe
eight = agt
nine = nege
ten = tien
(say: iyan; tware; dree; feerr; faif; ses; siyava; akht; niyakha; teen)
use google translater ! don't use numbers, right in words ^__^good luck.xxx
It depends with your speed but it can take you 10^18 light years to count from 1 to 10 sextillion.
I'll just write it out in Afrikaans- I'm not sure how to go about writing how to probounce it though. 10- tien 11- elf 12- twaalf 13- dertien 14- veertien 15- vyftien 16- sestien 17- sewentien 18- agtien 19- negentien 30- twintig
Locate 6,1Input "Your Name Please ",Nam$LOCATE 8,1FOR Count=1 to 10Print TAB(5) Count " > ";Nam$Next Count
1 = een 2 = twee 3 = drie 4 = vier 5 = vyf 6 = ses 7 = sewe 8 = agt 9 = nege 10 = tien
1 2 3 4 5 6 7 8 9 10
you cna you can only count backwards form 10-1
use google translater ! don't use numbers, right in words ^__^good luck.xxx
The Afrikaans numbers from 1 to 10 are as follows:1. een2. twee3. drie4. vier5. vyf6. ses7. sewe8. agt9. nege10. tien
It depends with your speed but it can take you 10^18 light years to count from 1 to 10 sextillion.
I'll just write it out in Afrikaans- I'm not sure how to go about writing how to probounce it though. 10- tien 11- elf 12- twaalf 13- dertien 14- veertien 15- vyftien 16- sestien 17- sewentien 18- agtien 19- negentien 30- twintig
int i; for (i=1; i<=10; i++) printf ("%d %d\n", i, i*i);
Locate 6,1Input "Your Name Please ",Nam$LOCATE 8,1FOR Count=1 to 10Print TAB(5) Count " > ";Nam$Next Count
eentweedrieviervyfsesseweagtnegetienelftwaalfdertienveertienvyftiensestiensewentienagtiennegentientwintig
public class DoWhileLoopDemo {public static void main(String[] args) {int count = 1;System.out.println("Printing Numbers from 1 to 10");do{System.out.println(count++);}while( count
it is 10. First, you need to count how many 1's there are. 1,2,3,4,5,6,7,8,9,10! There are 10.
1 = een 2 = twee 3 = drie 4 = vier 5 = vyf 6 = ses 7 = sewe 8 = agt 9 = nege 10 = tien