It is the number x such that 10^x = 2.
It is approx 0.3010
If a number has an antilog whose integer part is n, then the number has n-1 digits before the decimal point.
The answer is easy if you are familiar with scientific notation. The antilog of a number, whose integer part is n, has 10n in its scientific notation. Otherwise: the number that you want the antilog for will normally be in decimal form: consisting of an integer part, a decimal point and a fractional part. The number of integer digits in the antilog is one more than the integer part of the number being "antilogged" (exponentiated). antilog(0.1234) = 1.3286*100 = 1.3286 antilog(1.1234) = 1.3286*101 = 13.286 antilog(5.1234) = 1.3286*105 = 132860 antilog(-3.1234) = 1.3286*10-3 = 0.0013286
1.Using calculator-press the 'shift' button and then the log number to be converted. N:B:Estimate answer to 3 s.f 2.You can also fin antilog by raising the log by power 10.e.g antilog of x is 10^x
Find the base for the logarithm: it is likely to be 10 if you are a newcomer to logs or e (= 2.71828...) if you are more advanced. Then the antilog of x is 10x or ex.
Take the logarithm of your number, divide it by 3 then take the antilog.
Raise 10 to the power of the number. The antilog of 2 is 102 = 100 The antilog of 5 is 105 = 10,000 The antilog of 'pi' is 103.1416 = 1,385.46 (rounded)
how to find antilog(20/2) answer
Assuming working to base '10' , then Antilog 2.3909 is 10^(2.3909) = 245.9801149/ Remember for logarithms. log of a number is log(10)[number] Hence its antilog is 10^(log number).
It is 1013.309 . If your pocket calculator doesn't do 10x then you use antilog tables. It's a big number. 1013 x antilog of 0.309 might be more handy.
antilog((log90)/2)
Antilog 15.59 is the number whose logarithm is equal to 15.59. If y is the number whose logarithm is 15.59, then log y = 15.59. This is equivalent to y = 10^15.59. So we have: antilog 15.59 = 10^15.59 = 3.89045145E15
An antilog amplifier is also known as a logarithmic converter. This means that the input voltage is multiplied by a set number in order to obtain the output voltage.
Value of AntiLog (6) is 1,000,000.00
1: Calculate the square root, then calculate its square root; OR 2: Take the logarithm of the number, divide it by 4 then take the antilog.
Not enough information.The antilog of 1182 is 10 to the power 1182, or e to the power 1182, or some other number to the power 1182 - whatever you choose to use as your basis for logarithms.
Same as for positive numbers. On a scientific calculator, you press (base number) (inverse) (log) (your number). You can also use the power function: (base) (power) (exponent).An antilog is just a power. The antilog (base 10) of 3 is 10 to the power 3.As to the definition, 10 to the power -3 is defined as 1 / (10 to the power 3).Same as for positive numbers. On a scientific calculator, you press (base number) (inverse) (log) (your number). You can also use the power function: (base) (power) (exponent).An antilog is just a power. The antilog (base 10) of 3 is 10 to the power 3.As to the definition, 10 to the power -3 is defined as 1 / (10 to the power 3).Same as for positive numbers. On a scientific calculator, you press (base number) (inverse) (log) (your number). You can also use the power function: (base) (power) (exponent).An antilog is just a power. The antilog (base 10) of 3 is 10 to the power 3.As to the definition, 10 to the power -3 is defined as 1 / (10 to the power 3).Same as for positive numbers. On a scientific calculator, you press (base number) (inverse) (log) (your number). You can also use the power function: (base) (power) (exponent).An antilog is just a power. The antilog (base 10) of 3 is 10 to the power 3.As to the definition, 10 to the power -3 is defined as 1 / (10 to the power 3).
Formula- Antilog of x is equal to 10xGoing along with the following example, 102.6992 = 500.265 --------------------------------------------------------Find the antilog of 2.6992 . The number before the decimal point is 2, so the decimal point will be after the first 3 digits. From the antilog table, read off the row for .69 and column of 9; the number given in the table is 5000. The mean difference in the same row and under the column 2 is 2. To get the inverse of mantissa add 5000 + 2 = 5002. Now place a decimal point after the first 3 digits and you get the number 500.2 Thus antilog 2.6992 = 500.2 Example 2 : Find the antilog of 1.0913. The number before the decimal point is 1, the number of zeroes after the decimal point is zero. From the antilog table, read off the row for .09 and column of 1; the number given in the table is 1233. The mean difference in the same row and under the column 3 is 1. To get the inverse of mantissa add 1233 + 1 = 1234. Now place a decimal point before the first digit and you get the number 0.1234. 5.ApplicationsWe will now see how logarithms and antilogarithms of numbers are useful for calculations which are complicated or have very large/small numbers. Example 1 : Find 80.92 * 19.45. Let x = 80.92 * 19.45 Use the log function on both the sides. log x = log (80.92 * 19.45) log (80.92 * 19.45) = log 80.92 + log 19.45 ( from the laws of logarithms) From the log tables we get log 80.92 = 1.9080, log 19.45 = 1.2889 Thus log (80.92 * 19.45) = 1.9080 + 1.2889 = 3.1969 log x = 3.1969 Now use antilog functions on both the sides. x = antilog 3.196 From the antilog tables we see that the antilog of 3.1969 is 1573.0. Example 2 : Find (0.00541 * 4.39)71.35 Let x = (0.00541 * 4.39)71.35 Take log functions on both the sides. log x = log ( (0.00541 * 4.39) ) ñ log (71.25) ( from the laws of logarithms) First term on the RHS : log ( (0.00541 * 4.39) ) = log (0.00541 * 4.39 )‡ = 1/2 log (0.00541) + 1/2 log (4.39) log (0.00541) = - 2.2668 ‡ log (0.00541) = - 1.1334 log (4.39) = 0.6423 ‡ log (4.39) = 0.3212 Thus the first term on the RHS : -0.8122 The second term on the RHS : log (71.25) = 1.8527 _Thus log x = - 2.6649; in terms of bar, this can be written as 3.3351. Now take the antilog functions on both the sides, we get x = 0.002163.