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First, you write the symbol of oxygen, O. Then you draw the valence electron around it. Since oxygen has 8 electron, it has 2 in the first shell and 6 in the second shell, the number of valence electrons is 6. You draw the 6 electrons around the O.They should be coupled by 2.

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14y ago
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14y ago

Nitrogen has an atomic number of 7 and a mass number of 14.

This means that its nucleus is made up of 7 protons and 7 neutrons.

As the number of electrons is equal to the number of protons (except in an ion) there are 7 electrons in nitrogen.

This means that the first (inner) shell will have 2 electrons and the second shell will have 5 electrons.

The dot and cross diagram for N2 would show the electrons in the inner shell as above and then 3 dots and 3 crosses in the overlap zone for the outer shell with 2 dots to one side and 2 crosses to the other. This is a triple bond.

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13y ago

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.o:

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14y ago

Since Oxygen (O) is in group 6, it needs to gain two electrons ( gains -ve)

..

Oxygen is just :O:

O2 is

.. ..

:O: :O:

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Q: How do you draw the dot diagram for oxygen?
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