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4(w^2 + 3w + 1)
Wiki User
∙ 8y ago
To factor 4w^2 + 12w + 4 = 0, first divide the equation by 4 to simplify it: w^2 + 3w + 1 = 0. Then, decompose the middle term (3w) into two terms whose product is the product of the coefficient of w^2 and the constant term (1): (w+1)(w+1) = 0. Therefore, the factors are (w+1)(w+1) = 0.
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39 plus 12w equals 10?
39 + 12w = 1039 -10 = -12w29 = -12ww = -12/29 = -0.413
-3w-3x-7w+4x-2w?
-8w-7x
What is the area if perimeter is 96 and l equals 5w?
Assuming this question is asking about a rectangle: Perimeter = 2l + 2w and according to this problem Perimeter = 96, so 96 = 2l + 2w If l = 5w, then we can replace each l in the statement above with 5w, so 96 = 2(5w) + 2w 96 = 10w + 2w 96 = 12w 8 = w If 8 = w, and l = 5w, then l = 5 times 8 = 40 The area of a rectangle is length (l) times width (w), so A = lw A = (40) (8) A = 320 square units
If a storm window has an area of 400 square inches what are the dimensions if the window is 12 inches higher than it is wide?
This answer for each dimension is provided to 4 decimal places only.The height of the window is 26.8806 inches and the width is 14.8806 inches.For, let h equal the height and w the width.Thus in inches:1. h * w = 4002. h - w = 12We can rewrite 2. as h = w + 12Substituting h = w + 12 into 1. gives3. w (w + 12) = 400 thusw2 + 12w = 400w2 + 12w - 400 = 0Substituting the above values into the quadratic formulawhere the roots of aw2 + bw + c = (-b + or - ((b2 - 4ac) 1/2)) / 2a gives:w = (-12 + or - (122 - (4 * 1 * -400)1/2)) / 2 * 1= (-12 + or - (144 - -1600)1/2) / 2= (-12 + or - 17441/2) / 2= 14.8806 (to 4 decimal places only) and -26.8806(to 4 decimal places only)We can clearly discount the negative root. Therefore the width of the window is equal to 14.8806 inches (to 4 decimal places only).Substituting w = 14.8806 into 1. gives14.8806 * h = 400h = 400/14.8806h = 26.8806 (to 4 decimal places)
How does the decibel scale work?
The decibel scale is a "logarithmic" scale, meaning that in order to move up by the same amount from any starting point, you don't add the same amount, you multiply by the same amount.For example, if I increase the loudness of my harmonica from 1 watt to 2 watts, while you crank your electric guitar up from 1,000 watts to 2,000 watts, both of us doubled our original sound power, and increased our sound by the same number of decibels.It's important to understand that the number of decibels always means the size of the change from the original amount. Some number of decibels is not a quantity that you can hold in your hand. It's always a comparison between the original and the final. When you see a number of decibels stated, the original value is always lurking somewhere nearby, or else it's clearly understood.Increasing the original power means adding dB. Decreasing the original power means subtracting dB (or adding negative dB).Multiplying the original power by 10 is an increase of 10 dB. Dividing the original power by 10 is a decrease of 10 dB.Technically, the way to calculate the dB of change isdB = 10 times the log of [(new power) divided by (old power)].Some quick and easy approximate numbers to remember, so you don't have to calculate it every time:Multiply or divide by 2 ==> plus or minus 3 dBMultiply or divide by 4 ==> plus or minus 6 dBMultiply or divide by 5 ==> plus or minus 7 dBMultiply or divide by 8 ==> plus or minus 9 dBMultiply or divide by 10 ==> plus or minus 10 dB (definition)Example:-- Increase power from 1 watt to 40 watts ==> Multiply power by 40.x 40 = product of (10 x 2 x 2) = +10dB + 3db + 3db = +16 dB.This is exactly the same as the change from 1 billion watts to 40 billion watts ... still +16dB, because it's the changethat counts in dB.-- Decrease power from 100 watts to 25 watts. Divide 100 by 2 (get 50), then divide 50 by 2 (get 25).Divide by 2 the first time ==> minus 3 dB. Divide by 2 the second time ==> minus 3 more dB.So 25 watts is 6 dB below 100 watts.When referring to the standard decibel scale as a measurement of the intensity of sound, it is important to note that 0 dB is set at 10-12W*m^(-2). In the above equation for dB, if you are using the standard scale, always use 10-12 as your (old power) value.
39 plus 12w equals 10?
39 + 12w = 1039 -10 = -12w29 = -12ww = -12/29 = -0.413
What is the equation for 12w equals 48?
It is 12w = 48 or w = 4.
What is (4w plus 2w)2?
It is 12w.
What is the perimeter of 7x-7w 5x plus 6y 2y plus 3w?
12x+12y-12w
What expressions are equivalent to12w plus 6?
6(2w + 1)
Can someone find the answer 12x-14w plus 103y plus 72 plus 16-56 plus 0-65 plus 2w plus 0 equals?
12x-14w+103y+72+16-56+0-65+2w+0 original = 12x-14w+2w+103y+72+16-56+0-65+0 group = 12x-12w+103y-33 answer
Whats the answer to 12W-8?
20
What reasons are there to want to correct a lagging power factor?
When you have a lagging power factor, measuring instruments (i.e. AC energy meters etc..) will read high. For example, if you've actually used 12W, when a lagging power factor is present, the meter might read 13~14W.
What is the best company for plus size womens clothing?
One Stop Plus has a lot of clothing on sale and their size ranges from 12W to 44W. Simply Be has a smaller range from 10W to 28W, but they offer 30% off your first order.
What is the product of w and 12?
The product of w and 12 is 12w.
How many more sides does a decagon have than a hexagon?
4
Jane is 2 mi offshore in a boat and wishes to reach a coastal village 6 miles down a straight shoreline from the point nearest the boat She can row 2 mph and can walk 4 mph Where should she land her?
r = distance she rowedw = distance she walkedt = total time to reach villaget = r/2 + w/5r^2 = 2^2 + (6 - w)^2r = (4 + 36 - 12w + w^2)^(1/2)r = (w^2 - 12w + 40)^(1/2)t = (w^2 - 12w + 40)^(1/2)/2 + w/5t' = (1/2)(1/2)(w^2 - 12w + 40)^(-1/2)(2w - 12) + 1/5 = 0(1/2)(1/2)(w^2 - 12w + 40)^(-1/2)(2w - 12) = -1/5(1/2)(w - 6) = -1/5(w^2 - 12w + 40)^(1/2)5(w - 6) = -2(w^2 - 12w + 40)^(1/2)25(w^2 - 12w + 36) = 4(w^2 - 12w + 40)(25 - 4)w^2 + (-25*12 + 4*12)w + 25*36 - 4*40 = 021w^2 - 252w + 740 = 0w = 6.87, 5.13 midiscard 6.87 ( > 6)r = (w^2 - 12w + 40)^(1/2)r = 2.18 miShe should land her boat 5.13 miles away from village
