(x3 - 8) is factored thus: (x - 2)(x2 + 2x + 4) The easiest way to do this is to remember the formula: (a3 - b3) = (a - b)(a2 + ab + b2)
(2 - 3x)(9x^2 + 6x + 4)
Answer: (x - 2)(x² + 2x + 4)Factor the difference of cubes:a³ - b³ = (a - b)(a² + ab + b² )note 8 = 2³ = 8 ⇒ b = 2 , with a = xSox³ - 8= x³ - 2³= (x - 2)(x² + 2x + 2²) = (x - 2)(x² + 2x + 4)
(3x + 8)(3x - 8)
8(d-3)
7g-10h
8(y - 1)(y^2 + y + 1)
8(y - 1)(y^2 + y + 1)
(2 - 3x)(9x^2 + 6x + 4)
All that is factorable here is the common factor t.t3 - 8tt(t2 - 8)======
the answer is (3x-2)(9x squared+6x+4)
-4
The expression n2 - n - 56 factors to (n - 8)(n + 7).
9 minus 8
32a + 8= 8(4a+1)
000000
8 - (9 - t)
Answer: (x - 2)(x² + 2x + 4)Factor the difference of cubes:a³ - b³ = (a - b)(a² + ab + b² )note 8 = 2³ = 8 ⇒ b = 2 , with a = xSox³ - 8= x³ - 2³= (x - 2)(x² + 2x + 2²) = (x - 2)(x² + 2x + 4)