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How do you factorise x2-5x-50?
p2-5p-50= (p-10) (p+5)
Factorise x2 plus 5x?
x(x+5)
How do you Factorise 25xy plus 5yz?
25xy+5yz is 5y(5x+z) when factored
Why the expression 5x-6y will not factorise?
11
If 5x squared plus 2x equals 192 what is the value of x?
Factorise: 5x2 + 2x - 192 = (x - 6)(5x + 32) = 0; whence, x = 6 or -6.4.
How do you factorise x2-5x-50?
p2-5p-50= (p-10) (p+5)
How do we factorise (5x+15)/5?
qwertyuiopasdfjk
Factorise 5x squared plus 17x plus 6?
(5x + 2)(x + 3)
How do you factorise 5x plus 10?
you factor out the common 5so it would be: 5(x + 2)so that when you multiply back out 5 by x you get 5x and 5 by 2 you get 10
Factorise x2 plus 5x?
x(x+5)
Factorise 6x2 plus 5x plus 1?
6x^2 + 5x + 1 = (3x +1) (2x + 1)
How do you factorise x squared-5x-6?
1
How do you factorise 4x2 plus 5x - 6?
(4x-3)(x+2)
How do you factorise x squared - 5x - 6?
x^2 - 5x - 6 Since the coefficient of 'x^(2)' is '1' in this case. we look at the constant '6' . So write down all the factors of 6' . They are 1,2,3,&6. From these four number we select two numbers that add/subtract to '- So if we say -6 + 1 = -5 5'. The coefficient of 'x' Since 6 - 1 = 5 & 2 + 3 = 5 We need to think a little deeper. So we look at the mathemetical signs , which in this case are both negative (-). Since the sign in front of the '6' is negative, this means that the signs in the brackets are different. NB If it was a possitive both the signs in brackets would be the same either both (+) or both (-). So to have a '-5' we can say -6 + 1 = -5 So setting up the brackets ( x 6 )(x 1) So the signs will be (x - 6)( x + 1) Done!!!! Hope that helps!!!!
Can you Factorise 20x-28?
Yes and it is 4(5x-7) when factored
How do you Factorise 25xy plus 5yz?
25xy+5yz is 5y(5x+z) when factored
How do you factorise 5x squared minus 9x minus 2?
5x2 + 9x + 13 has no real factors.
