acceleration is the change in speed. Its unit is in [m/s^2 or m/s/s]. If at time t1, the speed is s1, and s2 at time t2, then acceleration = (s2-s1)/(t2-t1). That said, be aware of direction change too. The formula before only works when the direction is constant, and you can speak of speed, instead of velocity.
You can have acceleration even when the speed is constant. That happens when an object travels in a circle, for example. The acceleration is perpendicular to the velocity at each instance in time. Then acceleration, as a vector, is equal to dv/dt, where v is a vector which is time-varying (speed, on the other hand, is a scalar).
Acceleration = Change in Speed divided by Time over which the change takes place.
If acceleration is constant then Acc = [Final Speed - Initial speed] / Time
If not, Acc = gradient of Speed-Time graph.
If the speed is zero at the beginning of the given time ... the object accelerates
from rest ... then
Distance (here comes the formula you need to keep for later) = 1/2 a T2
Multiply each side of the equation by 2 :
2 D = a T2
Divide each side by T2 :
2D/T2 = a
Acceleration = 2 x Distance/Time2
And that's the answer to your question "How . . . ".
If you ran into this problem on a test and you didn't know that formula up there
in the third line, you'd immediately run out of steam and your palms would begin
to sweat fiercely.
Here's where that formula comes from. If you can get a grip on yourself and
think clearly, here's how to build it whenever you need it:
-- You know the Distance the object moved and the Time it took, and you know
that it started from rest and accelerated uniformly.
-- "Acceleration" means how much speed it picks up every second. If it starts
from zero, then its speed at the end of 'T' is [ a T ].
-- The object's average speed during that time is distance/time . . . that's the
definition of speed.
-- The "average" means 1/2 (beginning speed + ending speed). But the
beginning speed was zero, so the average = 1/2 (ending speed).
-- Three steps ago: ending speed = a T
-- Two steps ago: Average speed = distance/time
-- One step ago: Average speed = 1/2 (ending speed) = 1/2 (a T)
-- You have two expressions for the average speed, so the expressions are equal:
Distance/time = 1/2 (a T)
Multiply both sides by the time:
Distance = 1/2 a T2
And that's the formula up in the third line. The solution for the acceleration
continues under it.
speed = distance (meters) Divided by time (seconds) = speed in meters per seconds
distance traveled/time traveled
10ft in 5 seconds = 2ft/sec
Time = Speed/Accleration
only if acceleration is constant, and initial velocity is 0.
Acceleration = velocity/time
Velocity = time * acceleration
=====================
Time=Acceleration/Speed
48m in 4 seconds
To boost or to speed up!
To boost or to speed up!
Accelaration
Acceleration is any change in the speed or direction of an object's motion.
speed means - how fast your going . acceleration - is the change in speed. examples: I was going down the highway at 65mph (current speed). A corvette can accelerate from 30-70mph in 4 sec.
it changes the speed
To boost or to speed up!
To boost or to speed up!
velocity= distance/time=d/t accelaration= dv/dt
Yes because it is going to be helpful to find the derivative of certain equations such as velocity speed and accelaration
Accelaration
Acceleration is any change in the speed or direction of an object's motion.
the rate at which velocity changes velocity=speed in a given direction
Acceleration is an increase in change in speed over time of an object, and deceleration is a decrease in the change in speed over time of an object. -aerol-
speed means - how fast your going . acceleration - is the change in speed. examples: I was going down the highway at 65mph (current speed). A corvette can accelerate from 30-70mph in 4 sec.
Acceleration equals: final speed, minus original speed, divided by total time. Source: (http://www.scienceteacherprogram.org/physics/Torpie00-1.html)
a = (v2-v1)/t if velocity never changes then acceleration is always zero