How do you find accelaration using speed?

Answer 1

acceleration is the change in speed. Its unit is in [m/s^2 or m/s/s]. If at time t1, the speed is s1, and s2 at time t2, then acceleration = (s2-s1)/(t2-t1). That said, be aware of direction change too. The formula before only works when the direction is constant, and you can speak of speed, instead of velocity.

You can have acceleration even when the speed is constant. That happens when an object travels in a circle, for example. The acceleration is perpendicular to the velocity at each instance in time. Then acceleration, as a vector, is equal to dv/dt, where v is a vector which is time-varying (speed, on the other hand, is a scalar).

Answer 2

Acceleration = Change in Speed divided by Time over which the change takes place.

If acceleration is constant then Acc = [Final Speed - Initial speed] / Time

If not, Acc = gradient of Speed-Time graph.

Answer 3

If the speed is zero at the beginning of the given time ... the object accelerates

from rest ... then

Distance (here comes the formula you need to keep for later) = 1/2 a T2

Multiply each side of the equation by 2 :

2 D = a T2

Divide each side by T2 :

2D/T2 = a

Acceleration = 2 x Distance/Time2

And that's the answer to your question "How . . . ".

If you ran into this problem on a test and you didn't know that formula up there

in the third line, you'd immediately run out of steam and your palms would begin

to sweat fiercely.

Here's where that formula comes from. If you can get a grip on yourself and

think clearly, here's how to build it whenever you need it:

-- You know the Distance the object moved and the Time it took, and you know

that it started from rest and accelerated uniformly.

-- "Acceleration" means how much speed it picks up every second. If it starts

from zero, then its speed at the end of 'T' is [ a T ].

-- The object's average speed during that time is distance/time . . . that's the

definition of speed.

-- The "average" means 1/2 (beginning speed + ending speed). But the

beginning speed was zero, so the average = 1/2 (ending speed).

-- Three steps ago: ending speed = a T

-- Two steps ago: Average speed = distance/time

-- One step ago: Average speed = 1/2 (ending speed) = 1/2 (a T)

-- You have two expressions for the average speed, so the expressions are equal:

Distance/time = 1/2 (a T)

Multiply both sides by the time:

Distance = 1/2 a T2

And that's the formula up in the third line. The solution for the acceleration

continues under it.

Answer 4

speed = distance (meters) Divided by time (seconds) = speed in meters per seconds

distance traveled/time traveled

10ft in 5 seconds = 2ft/sec

Answer 5

Time = Speed/Accleration

only if acceleration is constant, and initial velocity is 0.

Answer 6

Acceleration = velocity/time

Velocity = time * acceleration

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Answer 7

Time=Acceleration/Speed

Answer 8

48m in 4 seconds