By summing the mathematical variables say;X1+X2+X3 Then, dividing by their average 3.
what exponential function is the average rate of change for the interval from x = 7 to x = 8.
Find the derivative
You measure the change in the vertical direction (rise) per unit change in the horizontal direction (run). The rate of change is constant between A and B if AB is a straight line. Take any two points, A = (xa, ya) and B = (xb, yb) then the average rate of change, between A and B = (yb- ya)/(xb- xa).
if a function is increasing, the average change of rate between any two points must be positive.
It would depend on what is changing and on what timescale. For example, the rate of change of speed (acceleration) can be either ms-2 or miles/hour2.
This is done with a process of limits. Average rate of change is, for example, (change of y) / (change of x). If you make "change of x" smaller and smaller, in theory (with certain assumptions, a bit too technical to mention here), you get closer and closer to the instant rate of change. In the "limit", when "change of x" approaches zero, you get the true instantaneous rate of change.
The rate, or rate of change is like an average all except it has to do with the slope of a line instead of a group of numbers. Finding the rate of change is like finding an average except you use the points on the graph instead of numbers in a group.
The change in y over the change in x
You cannot. Acceleration is the rate of change in velocity over time
you can compare two measurements using ratios to find the unit rate.
what exponential function is the average rate of change for the interval from x = 7 to x = 8.
The rate of changing the interval of 25 is 19.5. This is a math problem.
Fancy pants!
You find the average rate of change of the function. That gives you the derivative on different points of the graph.
Depends. Slope of tangent = instantaneous rate of change. Slope of secant = average rate of change.
If the function relating the two variables is differentiable, then the rate is the derivative.
Find the derivative